在 PHP 中从另一个函数调用一个函数
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Call a function from another function in PHP
提问by BB-8
I am struggling to implement a php code with the following structure:
我正在努力实现具有以下结构的 php 代码：
public function hookActionValidateOrder($params)
{
$invoice = new Address((int)$order->id_address_invoice);
$myStreet = $invoice->address1;
$myCity = $invoice->city;
$myPostcode = $invoice->postcode;
// ... SOME IRRELEVANT CODE HERE ...
$Tid = send($myStreet, $myCity, $myPostcode); /* Calling function send($a, $b, $c) */
}
public function send($a, $b, $c) /* function send($a, $b, $c) */
{
// ... CODE TO DO SOMETHING USING VARIABLES $a, $b, $c ...
}
The problem is, this code doesn′t seem to work. When I put it into a code validator, it says: "Function 'send()' does not exists". Tell me please Why is that so and how do I fix that?
问题是，这段代码似乎不起作用。当我将它放入代码验证器时，它说：“函数'send()'不存在”。请告诉我为什么会这样，我该如何解决？
回答by gaurav
If you are using a class, then you can use $thisfor calling the function:
如果您正在使用一个类，那么您可以$this用于调用该函数：
class Test {
public function say($a) {
return $a ;
}
public function tell() {
$c = "Hello World" ;
$a = $this->say($c) ;
return $a ;
}
}
$b= new Test() ;
echo $b->tell() ;
If you are using a normal function, then use closure:
如果您使用的是普通函数，则使用闭包：
function tell(){
$a = "Hello" ;
return function($b) use ($a){
return $a." ".$b ;
} ;
}
$s = tell() ;
echo $s("World") ;
回答by PHP Ninja
try this:
尝试这个：
class test
{
public function hookActionValidateOrder($params)
{
$invoice = new Address((int)$order->id_address_invoice);
$myStreet = $invoice->address1;
$myCity = $invoice->city;
$myPostcode = $invoice->postcode;
// ... SOME IRRELEVANT CODE HERE ...
$Tid = send($myStreet, $myCity, $myPostcode); /* Calling function send($a, $b, $c) */
}
}
class test1 extends test
{
public function send($a, $b, $c) /* function send($a, $b, $c) */
{
// ... CODE TO DO SOMETHING USING VARIABLES $a, $b, $c ...
}
}
You can solve this with extends one class to another class .
您可以通过将一个类扩展到另一个类来解决此问题。
回答by PHP Ninja
if you trying to use a Function or any code from the original page
in a secondary pagewithout including it , then usually it show you this Error
如果您尝试
在二级页面中使用函数或原始页面中的任何代码而不包含它，则通常会显示此错误
(.... ' string name , function Name ,.......etc ') does not exists
(.. ' 字符串名称 , 函数名称 ,.......etc ') 不存在
The solution is to includeit first in your secondary page and use :
解决方案是首先将其包含在您的辅助页面中并使用：
include("yourpage.php");
if notthen
see "@Gulshan" Comment about "extends" classes.
it causes the same problem
如果不是那么
看到有关“@Gulshan”评论“扩展”类。它会导致同样的问题
