php 如何在同一页面上放置两个表单?
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/14071250/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to place two forms on the same page?
提问by Alegro
I want to place both register and login form on the same page.
They both starts with:
我想将注册和登录表单放在同一页面上。
他们都开始于:
if (!empty($_POST)) ...
so, I need something like:
所以,我需要类似的东西:
if (!empty($_POST_01))... // regForm
and
if (!empty($_POST_02))... //loginForm
Also how to prevent executing first form if the second is busy, and vice versa (user clicks on both)
My idea is to create a simple variable on starting process, for example $x = 1and at the end of process $x = 0, so:
还有如何防止在第二个表单繁忙时执行第一个表单,反之亦然(用户同时点击两者)
我的想法是在启动过程中创建一个简单的变量,例如$x = 1,在过程结束时$x = 0,所以:
if ((!empty($_POST_01)) And $x = 0)...
Probably, there is a better way.
也许,有更好的方法。
回答by cristi _b
You could make two forms with 2 different actions
你可以用 2 个不同的动作制作两个表格
<form action="login.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="Login">
</form>
<br />
<form action="register.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="Register">
</form>
Or do this
或者这样做
<form action="doStuff.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="hidden" name="action" value="login">
<input type="submit" value="Login">
</form>
<br />
<form action="doStuff.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="hidden" name="action" value="register">
<input type="submit" value="Register">
</form>
Then you PHP file would work as a switch($_POST['action']) ... furthermore, they can't click on both links at the same time or make a simultaneous request, each submit is a separate request.
然后您的 PHP 文件将用作 switch($_POST['action']) ...此外,它们不能同时单击两个链接或同时发出请求,每次提交都是一个单独的请求。
Your PHP would then go on with the switch logic or have different php files doing a login procedure then a registration procedure
然后您的 PHP 将继续切换逻辑或使用不同的 php 文件执行登录程序然后执行注册程序
回答by Naftali aka Neal
Well you can have each form go to to a differentpage. (which is preferable)
那么您可以让每个表单转到不同的页面。(这是可取的)
Or have a different value for the a certain input and base posts on that:
或者对某个输入和基础帖子有不同的价值:
switch($_POST['submit']) {
case 'login':
//...
break;
case 'register':
//...
break;
}
回答by mark kasina
Give the submit buttons for both forms different names and use PHP to check which button has submitted data.
给两个表单的提交按钮指定不同的名称,并使用 PHP 来检查哪个按钮提交了数据。
Form one button - btn1 Form two button -btn2
一键成型-btn1 成型二按键-btn2
PHP Code:
PHP代码:
if($_POST['btn1']){
//Login
}elseif($_POST['btn2']){
//Register
}
回答by gezimi005
Hope this will help you. Assumed that login form has: username and password inputs.
希望这会帮助你。假设登录表单有:用户名和密码输入。
if(isset($_POST['username']) && trim($_POST['username']) != "" && isset($_POST['password']) && trim($_POST['password']) != ""){
//login
} else {
//register
}
回答by Rayobeats
You can use this easiest method.
您可以使用这种最简单的方法。
<form action="validator.php" method="post" id="form1">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="submit" form="form1">
</form>
<br />
<form action="validator.php" method="post" id="form2">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="submit" form="form2">
</form>
回答by Adem Büyük
Here are two form with two submit button:
这是两个带有两个提交按钮的表单:
<form method="post" action="page.php">
<input type="submit" name="btnPostMe1" value="Confirm"/>
</form>
<form method="post" action="page.php">
<input type="submit" name="btnPostMe2" value="Confirm"/>
</form>
And here is your PHP code:
这是您的 PHP 代码:
if (isset($_POST['btnPostMe1'])) { //your code 1 }
if (isset($_POST['btnPostMe2'])) { //your code 2 }

