Typescript 中的匿名类
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Anonymous class in Typescript
提问by ic3
Getting some trouble to do the following in typescript. I've the following interface defined :
在打字稿中执行以下操作时遇到一些麻烦。我定义了以下接口：
interface RendererCallback {
getNode():HTMLElement;
getTable();
}
There is a method expecting a RenderCallback object like :
有一种方法需要 RenderCallback 对象，例如：
render( callback:RendererCallback )
How do I create an anonymous instance in the middle of my code :
如何在我的代码中间创建一个匿名实例：
myObject.render( new .. {
getNode() {
return myNode;
}
getTable() {
.. some code...
return something;
}
} );
回答by MgSam
You can use anonymous objects and lambdas:
您可以使用匿名对象和 lambdas：
myObject.render({
getNode: () => { doSomething...; return myNode },
getTable: () => myTable
});
Note, the newkeyword is not used.
请注意，new未使用关键字。
回答by stuffins
Typescript now supports class expressions so you can make actual anonymous classes.
Typescript 现在支持类表达式，因此您可以创建实际的匿名类。
myObject.render( new class {
getNode() {
return myNode;
}
getTable() {
.. some code...
return something;
}
} );
This has the benefit of thisnot being inferred to be anywithin the anonymous class' methods.
这样做的好处是this不会被推断为any在匿名类的方法中。
回答by Alex Dresko
Here's a full code sample that works:
这是一个有效的完整代码示例：
interface RendererCallback {
getNode():HTMLElement;
getTable();
}
class thing {
render(callback: RendererCallback) {
}
}
var myObject = new thing();
myObject.render( {
getNode() {
return null;
},
getTable() {
}
}
);
回答by joeystdio
I find it to nice to declare it like this:
我发现像这样声明它很好：
propertyName: RendererCallback = {
getNode: () => myNode, // no braces needed to only return something
getTable() => {
.. some code...
return something;
}
};
