Laravel 5:如何通过构造函数添加 Auth::user()->id ?
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Laravel 5: How to add Auth::user()->id through the constructor ?
提问by Vince
I can get the ID of the authenticated user like this:
我可以像这样获取经过身份验证的用户的 ID:
Auth::user()->id = $id;
Great it works, ... but I have a load of methods which need it and I want a cleaner way of adding it to the class as a whole,so I can just reference the $id in each method. I was thinking of putting it into the constructor, but as Auth::user is a static, I am making a mess of things and don't know how to do it.
太好了,它有效,...但我有很多方法需要它,我想要一种更简洁的方式将它作为一个整体添加到类中,所以我可以在每个方法中引用 $id。我想把它放到构造函数中,但由于 Auth::user 是一个静态的,我把事情弄得一团糟,不知道该怎么做。
Many thanks for your help !
非常感谢您的帮助 !
采纳答案by rotvulpix
You can use Auth::user() in the whole application. It doesn't matter where you are. But, in response to your question, you can use the 'Controller' class present in your controllers folder. Add a constructor there and make the reference to the user ID.
您可以在整个应用程序中使用 Auth::user()。你在哪里并不重要。但是,为了回答您的问题,您可以使用控制器文件夹中的“控制器”类。在那里添加一个构造函数并引用用户 ID。
<?php namespace App\Http\Controllers;
use Illuminate\Foundation\Bus\DispatchesCommands;
use Illuminate\Routing\Controller as BaseController;
use Illuminate\Foundation\Validation\ValidatesRequests;
/* Don't forget to add the reference to Auth */
use Auth;
abstract class Controller extends BaseController {
use DispatchesCommands, ValidatesRequests;
function __construct() {
$this->userID = Auth::user()?Auth::user()->id:null;
}
}
Then, in any method of any controller you can use the $this->userID variable.
然后,在任何控制器的任何方法中,您都可以使用 $this->userID 变量。
回答by Dwight
Instead of using the Facade you can inject the contract for the authentication class and then set the user ID on your controller. Like @rotvulpix showed you could put this on your base controller so that all child controllers have access to the user ID too.
您可以为身份验证类注入合约,然后在控制器上设置用户 ID,而不是使用 Facade。就像@rotvulpix 展示的那样,你可以把它放在你的基本控制器上,这样所有的子控制器也可以访问用户 ID。
<?php
namespace App\Http\Controllers;
use Illuminate\Contracts\Auth\Guard;
class FooController extends Controller
{
/**
* The authenticated user ID.
*
* @var int
*/
protected $userId;
/**
* Construct the controller.
*
* @param \Illuminate\Contracts\Auth\Guard $auth
* @return void
*/
public function __construct(Guard $auth)
{
$this->userId = $auth->id();
}
}
The guard has an id()
method which returns void
if no user is logged in, which is a little easier than having to go through user()->id
.
守卫有一个id()
方法,它void
在没有用户登录时返回,这比必须通过 更容易一些user()->id
。
回答by Ali Sherafat
Laravel >= 5.3
Laravel >= 5.3
you can't access the session or authenticated user in your controller's constructor because the middleware has not run yet.
您无法在控制器的构造函数中访问会话或经过身份验证的用户,因为中间件尚未运行。
As an alternative, you may define a Closure based middleware directly in your controller's constructor. Before using this feature, make sure that your application is running Laravel 5.3.4
or above:
作为替代方案,您可以直接在控制器的构造函数中定义基于闭包的中间件。在使用此功能之前,请确保您的应用程序正在运行 Laravel5.3.4
或更高版本:
class UserController extends Controller {
protected $userId;
public function __construct() {
$this->middleware(function (Request $request, $next) {
if (!\Auth::check()) {
return redirect('/login');
}
$this->userId = \Auth::id(); // you can access user id here
return $next($request);
});
}
}