PHP 卷曲,POST JSON

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时间:2020-08-25 12:29:21  来源:igfitidea点击:

PHP cURL, POST JSON

phpcurllibcurl

提问by Michael

I need to POST the following JSON code, but for some reason it is not working. Below is the code that I have.

我需要发布以下 JSON 代码,但由于某种原因它不起作用。下面是我拥有的代码。

$fieldString = "395609399";
//the curl request processor
function processCurlJsonrequest($URL, $fieldString) { //Initiate cURL request and send back the result
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_HTTPHEADERS, array('Content-Type: application/json'));
    curl_setopt($ch, CURLOPT_URL, $URL);
    curl_setopt($ch, CURLOPT_USERAGENT, $this->_agent);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
    curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
    curl_setopt($ch, CURLOPT_COOKIEFILE, $this->_cookie_file_path);
    curl_setopt($ch, CURLOPT_COOKIEJAR, $this->_cookie_file_path);
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE);
    curl_setopt($ch, CURLOPT_VERBOSE, TRUE);
    if ($fieldCount) { // in case of post fields present then pass it on
        curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode("{categoryId: $fieldString}"));
        curl_setopt($ch, CURLOPT_POST, 1);
    }
    $resulta = curl_exec($ch);
    if (curl_errno($ch)) {
        print curl_error($ch);
    } else {
        curl_close($ch);
    }
    return $resulta;
}

Here is the function which calls the cURL request:

这是调用 cURL 请求的函数:

function get_cat($categoryId, $URL) {
    $fields = array(
        "categoryId" => $categoryId
    );
    $fields_string = $fields;
    return $this->processCurlJsonrequest($URL, $fields_string);
}

回答by netcoder

The bit that is the problem is:

问题在于:

curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode("{categoryId: $fieldString}"));

CURLOPT_POSTFIELDS will accept either an array of parameters, or a URL-encoded string of parameters:

CURLOPT_POSTFIELDS 将接受参数数组或 URL 编码的参数字符串:

curl_setopt($ch, CURLOPT_POSTFIELDS, array('json'=>json_encode($stuff)));
curl_setopt($ch, CURLOPT_POSTFIELDS, 'json='.urlencode(json_encode($stuff)));

Where jsonwill be the name of the POST field (i.e.: will result in $_POST['json']being accessible).

jsonPOST 字段的名称在哪里(即:将导致$_POST['json']可访问)。

回答by Atef

Send your text without JSON encoding, and add this header code:

发送不带 JSON 编码的文本,并添加以下标头代码:

curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: application/json; charset=utf-8","Accept:application/json, text/javascript, */*; q=0.01")); 

回答by jussil

With the initial example, working code should be like this:

对于初始示例,工作代码应如下所示:

//the curl request processor
function processCurlJsonrequest($URL, $fieldString) { //Initiate cURL request and send back the result
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));
    curl_setopt($ch, CURLOPT_URL, $URL);
    curl_setopt($ch, CURLOPT_USERAGENT, $this->_agent);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
    curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
    curl_setopt($ch, CURLOPT_COOKIEFILE, $this->_cookie_file_path);
    curl_setopt($ch, CURLOPT_COOKIEJAR, $this->_cookie_file_path);
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE);
    curl_setopt($ch, CURLOPT_VERBOSE, TRUE);
    curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode(array("myJsonData" => "test")));
    curl_setopt($ch, CURLOPT_POST, 1); 
    $resulta = curl_exec($ch);
    if (curl_errno($ch)) {
        print curl_error($ch);
    } else {
        curl_close($ch);
    }
    return $resulta;
}

回答by jazzdrive3

I had issues sending JSON via cURL, and the problem was that I was not explicitly setting the content length in the header.

我在通过 cURL 发送 JSON 时遇到了问题,问题是我没有在标头中明确设置内容长度。

So the Header should be:

所以标题应该是:

curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json', 'Content-Length: ' . strlen($json)));

回答by mal

It's pretty simple really, make sure you've set the extra Content-Type header set for json, and then CURLOPT_POSTFIELDS can take the json as a string. No encoding necessary.

这真的很简单,确保您已经为 json 设置了额外的 Content-Type 标头,然后 CURLOPT_POSTFIELDS 可以将 json 作为字符串。无需编码。