bash 如何在bash中循环遍历一系列十进制数？
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How to loop through a range of decimal numbers in bash?
提问by izxle
I'd like to generate a sequence of equally spaced decimal numbers.
我想生成一系列等距十进制数。
For example, I want to echoall numbers between 3.0and 4.5, with step 0.1. I tried $ for i {3.0..4.5..0.1}; do echo $i; done, but this gives an error.
例如，我想将和echo之间的所有数字与 step 。我试过了，但这会出错。3.04.50.1$ for i {3.0..4.5..0.1}; do echo $i; done
I also tried $ for i in $(seq 3.0 4.5 0.1); do echo $i; donebut nothing happens.
我也尝试过，$ for i in $(seq 3.0 4.5 0.1); do echo $i; done但没有任何反应。
回答by Ole Tange
I also tried $ for i in $(seq 3.0 4.5 0.1); do echo $i; done but nothing happens.
我也试过 $ for i in $(seq 3.0 4.5 0.1); 做回声 $i; 完成但没有任何反应。
The order is wrong:
顺序错了：
$ for i in $(seq 3.0 0.1 4.5); do echo $i; done
回答by drpetermolnar
If you're looking for a loop from 3.5 to 4.5 in 0.1 steps this would work
如果您在 0.1 步中寻找从 3.5 到 4.5 的循环，这将起作用
for x in {35..45}; do
y=`bc <<< "scale=1; $x/10"`
echo $y
done
The same with 0.01 steps
与 0.01 步相同
for x in {350..450}; do
y=`bc <<< "scale=2; $x/100"`
echo $y
done
回答by bmscomp
for i in {3.0,4.5,0.1}; do echo $i; done
