bash 如何使用bash脚本并排打印两个数组？
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How to print two arrays side by side with bash script?
提问by Aslet
I couldn't find a good and simple answer to this question neither on google nor here on stackoverflow.
无论是在 google 上还是在 stackoverflow 上，我都找不到这个问题的好的和简单的答案。
Basically I have two arrays that I need to print into the terminal side by side since one array is a list of terms and the other the terms's definitions. Does anyone know a good way of doing this?
基本上我有两个数组需要并排打印到终端中，因为一个数组是术语列表，另一个是术语的定义。有谁知道这样做的好方法吗？
Thanks in advance.
提前致谢。
回答by rici
Here's a "one-liner":
这是一个“单行”：
paste <(printf "%s\n" "${terms[@]}") <(printf "%s\n" "${defs[@]}")
This will create lines consisting of a term and a def separated by a tab, which might not, strictly speaking, be "side by side" (since they're not really in columns). If you knew how wide the first column should be, you could use something like:
这将创建由一个由制表符分隔的 term 和 def 组成的行，严格来说，这可能不是“并排”（因为它们实际上不在列中）。如果您知道第一列应该有多宽，您可以使用以下内容：
paste -d' ' <(printf "%-12.12s\n" "${terms[@]}") <(printf "%s\n" "${defs[@]}")
which will pad or truncate the terms to 12 characters exactly, and then put a space between the two columns instead of a tab (-d' ').
这会将术语填充或截断为 12 个字符，然后在两列之间放置一个空格而不是制表符 ( -d' ')。
回答by jordanm
You can use a C-style for loop to accomplish this, assuming both arrays are the same length:
您可以使用 C 样式的 for 循环来完成此操作，假设两个数组的长度相同：
for ((i=0; i<=${#arr1[@]}; i++)); do
printf '%s %s\n' "${arr1[i]}" "${arr2[i]}"
done
