php 从php中的图像读取地理标记数据
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Reading Geotag data from image in php
提问by ingh.am
Does anyone know if there is a way to read geotag data from photos in PHP?
有谁知道是否有办法从 PHP 中的照片中读取地理标记数据？
Thanks
谢谢
回答by Will Coughlin
Like everyone else has said, exif_read_data(); will do it. To go ahead and get all of the data, use these args:
就像其他人所说的那样，exif_read_data(); 会做的。要继续获取所有数据，请使用以下参数：
exif_read_data($img, 0, true); // where $img is the path to your image
This function can only read headers from tiffs and jpegs and I'm pretty sure only jpegs may contain geotags. I've written a simple php script for use in the command line and posted it as a gist on github.
这个函数只能从 tiffs 和 jpegs 读取标题，我很确定只有 jpegs 可能包含地理标签。我编写了一个简单的 php 脚本以在命令行中使用，并将其作为要点发布在 github 上。
Run the script like this: php exif.php
像这样运行脚本：php exif.php
It will echo out an array. Look for the coordinates here:
它会回显一个数组。在此处查找坐标：
[GPS] => Array
[GPSLatitudeRef] => N
[GPSLatitude] => Array
[0] => 30/1
[1] => 1589/100
[2] => 0/1
[GPSLongitudeRef] => W
[GPSLongitude] => Array
[0] => 87/1
[1] => 3609/100
[2] => 0/1
[GPSAltitudeRef] =>
[GPSAltitude] => 18289/454
[GPSTimeStamp] => Array
[0] => 20/1
[1] => 22/1
[2] => 2065/1
[GPSImgDirectionRef] => T
[GPSImgDirection] => 34765/689
The Latitude and Longitude arrays contain three values: 0 is for degrees, 1 is for minutes and 2 is for seconds. If you see something like "1589/100" this is equal to 15.89. So for the GPSLongitude array, 3609/100 is equal to 36.09.
Latitude 和 Longitude 数组包含三个值：0 表示度数，1 表示分钟，2 表示秒。如果您看到类似“1589/100”的内容，则等于 15.89。因此对于 GPSLongitude 数组，3609/100 等于 36.09。
Convert the coordinates from degrees-minutes-second form to decimal form here http://www.satsig.net/degrees-minutes-seconds-calculator.htm
在此处将坐标从度-分-秒形式转换为十进制形式http://www.satsig.net/degrees-minutes-seconds-calculator.htm
If the latitude is South, dont forget to make it negative. If the longitude is west, make that negative. The coodinates from the above data are: 30.26483, -87.6015
如果纬度是南，不要忘记使它为负。如果经度为西，则将其设为负值。上述数据的坐标为：30.26483，-87.6015
回答by LoneWOLFs
Will Coughlin's answer is correct though I formulated a function for quick reference in case someone stumbles upon the same problem.
Will Coughlin的回答是正确的，尽管我制定了一个功能以供快速参考，以防有人偶然发现同样的问题。
/**
* Returns an array of latitude and longitude from the Image file
* @param image $file
* @return multitype:number |boolean
*/
function read_gps_location($file){
if (is_file($file)) {
$info = exif_read_data($file);
if (isset($info['GPSLatitude']) && isset($info['GPSLongitude']) &&
isset($info['GPSLatitudeRef']) && isset($info['GPSLongitudeRef']) &&
in_array($info['GPSLatitudeRef'], array('E','W','N','S')) && in_array($info['GPSLongitudeRef'], array('E','W','N','S'))) {
$GPSLatitudeRef = strtolower(trim($info['GPSLatitudeRef']));
$GPSLongitudeRef = strtolower(trim($info['GPSLongitudeRef']));
$lat_degrees_a = explode('/',$info['GPSLatitude'][0]);
$lat_minutes_a = explode('/',$info['GPSLatitude'][1]);
$lat_seconds_a = explode('/',$info['GPSLatitude'][2]);
$lng_degrees_a = explode('/',$info['GPSLongitude'][0]);
$lng_minutes_a = explode('/',$info['GPSLongitude'][1]);
$lng_seconds_a = explode('/',$info['GPSLongitude'][2]);
$lat_degrees = $lat_degrees_a[0] / $lat_degrees_a[1];
$lat_minutes = $lat_minutes_a[0] / $lat_minutes_a[1];
$lat_seconds = $lat_seconds_a[0] / $lat_seconds_a[1];
$lng_degrees = $lng_degrees_a[0] / $lng_degrees_a[1];
$lng_minutes = $lng_minutes_a[0] / $lng_minutes_a[1];
$lng_seconds = $lng_seconds_a[0] / $lng_seconds_a[1];
$lat = (float) $lat_degrees+((($lat_minutes*60)+($lat_seconds))/3600);
$lng = (float) $lng_degrees+((($lng_minutes*60)+($lng_seconds))/3600);
//If the latitude is South, make it negative.
//If the longitude is west, make it negative
$GPSLatitudeRef == 's' ? $lat *= -1 : '';
$GPSLongitudeRef == 'w' ? $lng *= -1 : '';
return array(
'lat' => $lat,
'lng' => $lng
);
}
}
return false;
}
Hope it helps someone.
希望它可以帮助某人。
回答by Raghwendra Pathak
Call this function with filename. I testet it and it works prefectly.
使用文件名调用此函数。我测试它，它工作得很好。
Call example:
调用示例：
$fileName='xxxxxx'; //or $fileName='xxxxxxxxx';
echo $returned_data = triphoto_getGPS($fileName);
Function:
功能：
function triphoto_getGPS($fileName)
{
//get the EXIF all metadata from Images
$exif = exif_read_data($fileName);
if(isset($exif["GPSLatitudeRef"])) {
$LatM = 1; $LongM = 1;
if($exif["GPSLatitudeRef"] == 'S') {
$LatM = -1;
}
if($exif["GPSLongitudeRef"] == 'W') {
$LongM = -1;
}
//get the GPS data
$gps['LatDegree']=$exif["GPSLatitude"][0];
$gps['LatMinute']=$exif["GPSLatitude"][1];
$gps['LatgSeconds']=$exif["GPSLatitude"][2];
$gps['LongDegree']=$exif["GPSLongitude"][0];
$gps['LongMinute']=$exif["GPSLongitude"][1];
$gps['LongSeconds']=$exif["GPSLongitude"][2];
//convert strings to numbers
foreach($gps as $key => $value){
$pos = strpos($value, '/');
if($pos !== false){
$temp = explode('/',$value);
$gps[$key] = $temp[0] / $temp[1];
}
}
//calculate the decimal degree
$result['latitude'] = $LatM * ($gps['LatDegree'] + ($gps['LatMinute'] / 60) + ($gps['LatgSeconds'] / 3600));
$result['longitude'] = $LongM * ($gps['LongDegree'] + ($gps['LongMinute'] / 60) + ($gps['LongSeconds'] / 3600));
$result['datetime'] = $exif["DateTime"];
return $result;
}
}
回答by svoop
回答by Hymanbot
You can use the exif_read_data()function if the geotag data is embedded in the EXIF data.
exif_read_data()如果地理标记数据嵌入在 EXIF 数据中，则可以使用该函数。
回答by Web Developer in Pune
Install Intervention\Imageby following command.
Intervention\Image按照以下命令安装。
Reference: http://image.intervention.io/getting_started/installation
参考：http: //image.intervention.io/getting_started/installation
composer require intervention/image
composer require intervention/image
Update config/app.php
更新 config/app.php
'providers' => [
Intervention\Image\ImageServiceProvider::class
],
'aliases' => [
'Image' => Intervention\Image\Facades\Image::class
]
'providers' => [
Intervention\Image\ImageServiceProvider::class
],
'aliases' => [
'Image' => Intervention\Image\Facades\Image::class
]
Use Library:
使用库：
$data = Image::make(public_path('IMG.jpg'))->exif();
if(isset($data['GPSLatitude'])) {
$lat = eval('return ' . $data['GPSLatitude'][0] . ';')
+ (eval('return ' . $data['GPSLatitude'][1] . ';') / 60)
+ (eval('return ' . $data['GPSLatitude'][2] . ';') / 3600);
$lng = eval('return ' . $data['GPSLongitude'][0] . ';')
+ (eval('return ' . $data['GPSLongitude'][1] . ';') / 60)
+ (eval('return ' . $data['GPSLongitude'][2] . ';') / 3600);
echo "$lat, $lng";
} else {
echo "No GPS Info";
}
$data = Image::make(public_path('IMG.jpg'))->exif();
if(isset($data['GPSLatitude'])) {
$lat = eval('return ' . $data['GPSLatitude'][0] . ';')
+ (eval('return ' . $data['GPSLatitude'][1] . ';') / 60)
+ (eval('return ' . $data['GPSLatitude'][2] . ';') / 3600);
$lng = eval('return ' . $data['GPSLongitude'][0] . ';')
+ (eval('return ' . $data['GPSLongitude'][1] . ';') / 60)
+ (eval('return ' . $data['GPSLongitude'][2] . ';') / 3600);
echo "$lat, $lng";
} else {
echo "No GPS Info";
}
