如何将 json 转换为 Laravel Eloquent 模型？
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How can I convert json to a Laravel Eloquent Model?
提问by Zephram
if I have an Eloquent Model called Post, and the mysql table has:
如果我有一个名为 Post 的 Eloquent 模型，并且 mysql 表有：
integer ID, string Text
整数 ID，字符串 文本
How do I convert this JSon:
我如何转换这个 JSon：
{ post: { text: 'my text' } }
To the relevant Post object that, once received in the controller, I can save to the database like this:
对于相关的 Post 对象，一旦在控制器中接收到，我就可以像这样保存到数据库中：
public function store(Post $post)
{
$post->save();
}
I'm not looking to build the logic that would do that for me, but for the Laravel way (or could it be that there isn't one? I googled it with no relevant results).
我不是要构建可以为我做到这一点的逻辑，而是为 Laravel 方式（或者可能没有？我用谷歌搜索它没有相关结果）。
回答by Bart?omiej Sobieszek
- Convert json to array
Hydrate model from array
$data = '{ "unique_id_001":{"name":"John","email":"[email protected]"}, "unique_id_002":{"name":"Ken","email":"[email protected]"} }'; $object = (array)json_decode($data); $collection = \App\User::hydrate($object); $collection = $collection->flatten(); // get rid of unique_id_XXX /* Collection {#236 ▼ #items: array:2 [▼ 0 => User {#239 ?} 1 => User {#240 ?} ] } */ dd($collection);
- 将json转换为数组
来自阵列的水合物模型
$data = '{ "unique_id_001":{"name":"John","email":"[email protected]"}, "unique_id_002":{"name":"Ken","email":"[email protected]"} }'; $object = (array)json_decode($data); $collection = \App\User::hydrate($object); $collection = $collection->flatten(); // get rid of unique_id_XXX /* Collection {#236 ▼ #items: array:2 [▼ 0 => User {#239 ?} 1 => User {#240 ?} ] } */ dd($collection);
回答by AlbinoDrought
filllooks like the method you want. To avoid adding every attribute to your $filledarray, which you would need to do if you wanted to use the fillmethod, you can use the forceFillmethod.
fill看起来像你想要的方法。为了避免将每个属性添加到您的$filled数组中，如果您想使用该fill方法，您需要这样做，您可以使用该forceFill方法。
It accepts an associative array of attributes, so the JSON will have to be decoded, and we'll have to get the inner postkey:
它接受一个关联的属性数组，因此必须对 JSON 进行解码，并且我们必须获得内部post键：
$rawJson = "{ post: { text: 'my text' } }";
$decodedAsArray = json_decode($rawJson, true);
$innerPost = $decodedAsArray['post'];
Once we have the decoded data, we can create an instance of the Posteloquent model and call forceFillon it:
一旦我们有了解码的数据，我们就可以创建一个Posteloquent 模型的实例并调用forceFill它：
$post = new Post();
$post->forceFill($innerPost);
$post->save();
This is similar to doing:
这类似于执行以下操作：
$post = new Post();
foreach ($innerPost as $key => $value) {
$post->$key = $value;
}
$post->save();
回答by Shahaf Antwarg
Just turn it to array and fill an eloquent
只要把它变成数组并填充一个雄辩的
$arr = json_decode($json, true);
$post = new Post;
$post->fill($arr);
回答by Odinovsky
Can you try it like this?
你可以这样试试吗？
public function store($poststuff)
{
$post = new Post;
$post->text = $poststuff['text'];
$post->save();
}
回答by tanvir993
It's way simple as like followings:
它的方式很简单，如下所示：
$json_post = { "post": { "text": "my text" } };
$post = new Post(
json_decode($json_post, true)
);
Now, you can run all eloquent methods on the most $post, ex:
现在，您可以在最 $post 上运行所有 eloquent 方法，例如：
$post->save()
I tested with laravel v7.11.0
我用 laravel v7.11.0 测试过
