Android 如何从电话间隙中的经纬度获取城市名称？
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How to get city name from latitude and longitude in phone gap?
提问by Vinod
I am able to get get full address from current latitude and longitude. but how can I get only city name from full address. this is my code.
我能够从当前纬度和经度获取完整地址。但是我怎样才能从完整地址中只获取城市名称。这是我的代码。
var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);
//alert("Else loop" + latlng);
geocoder.geocode({
'latLng': latlng
}, function(results, status) {
//alert("Else loop1");
if (status == google.maps.GeocoderStatus.OK) {
if (results[0]) {
var add = results[0].formatted_address;
alert("Full address is: " + add);
} else {
alert("address not found");
}
} else {
//document.getElementById("location").innerHTML="Geocoder failed due to: " + status;
//alert("Geocoder failed due to: " + status);
}
});
回答by Vinod
var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);
geocoder.geocode(
{'latLng': latlng},
function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (results[0]) {
var add= results[0].formatted_address ;
var value=add.split(",");
count=value.length;
country=value[count-1];
state=value[count-2];
city=value[count-3];
alert("city name is: " + city);
}
else {
alert("address not found");
}
}
else {
alert("Geocoder failed due to: " + status);
}
}
);
Split the full address with "," as delimiter and get the city name..
用“,”作为分隔符分割完整地址并获得城市名称。
回答by rinkesh
Clean example to get location from lat and lang and parsing result. based on Google Reverse Geocoding
从 lat 和 lang 获取位置并解析结果的干净示例。基于谷歌反向地理编码
var geocodingAPI = "https://maps.googleapis.com/maps/api/geocode/json?latlng=23.714224,78.961452&key=YOUR_SERVER_API_KEY";
$.getJSON(geocodingAPI, function (json) {
if (json.status == "OK") {
//Check result 0
var result = json.results[0];
//look for locality tag and administrative_area_level_1
var city = "";
var state = "";
for (var i = 0, len = result.address_components.length; i < len; i++) {
var ac = result.address_components[i];
if (ac.types.indexOf("administrative_area_level_1") >= 0) state = ac.short_name;
}
if (state != '') {
console.log("Hello to you out there in " + city + ", " + state + "!");
}
}
});
回答by Damien Roelens
You can find documentation here :
您可以在此处找到文档：
https://developers.google.com/maps/documentation/geocoding/?hl=fr#ReverseGeocoding
https://developers.google.com/maps/documentation/geocoding/?hl=fr#ReverseGeocoding
But you can see in your "results" which item is the city without spliting the object.
但是您可以在“结果”中看到哪个项目是城市而无需拆分对象。
So you can do :
所以你可以这样做：
country=results[0]['address_components'][6].long_name;
state=results[0]['address_components'][5].long_name;
city=results[0]['address_components'][4].long_name;
Be carefull, the numbers "4,5,6" can change by the country. So it safier to test like that :
请注意，数字“4、5、6”可能因国家/地区而异。所以这样测试更安全：
Getting street,city and country by reverse geocoding using google
回答by manukv
Take a look at Google Reverse Geocoding
看看谷歌反向地理编码
http://maps.google.com/maps/api/geocode/xml?latlng=YourLatitude,YourLongitude&sensor=false&key=API_KEY
This is already asked here
回答by Sivart
This is how I I'm doing it. Was afraid to use a comma delimiter.
我就是这样做的。害怕使用逗号分隔符。
function ReverseGeoToCity(lat, lng, callback) {
var latlng = new google.maps.LatLng(lat, lng);
geocoder.geocode({'latLng': latlng}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (results[1]) {
var properName = ", ";
for(i=0; i<results[1].address_components.length; i++){
if (results[1].address_components[i].types[0] == "locality")
properName = results[1].address_components[i].short_name + properName;
if (results[1].address_components[i].types[0] == "administrative_area_level_1")
properName += results[1].address_components[i].short_name;
}
callback(properName);
} else {
alert('No results found');
}
} else {
alert('Geocoder failed due to: ' + status);
}
});
}
