如何将函数的结果存储在 Python 中的变量中？
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How can I store a result of a function in a variable in Python?
提问by Shawdotion
I'm trying to store the result of random.randominto a variable like so:
我试图将结果存储random.random到一个变量中，如下所示：
import random
def randombb():
a = random.random()
print(a)
randombb()
How can I properly get a?
我怎样才能正确地得到一个？
Thanks.
谢谢。
采纳答案by mgilson
Generally, you returnthe value. Once you've done that, you can assign a name to the return value just like anything else:
一般来说，你return的价值。完成后，您可以像其他任何事情一样为返回值分配一个名称：
def randombb():
return random.random()
a = randombb()
As a side note -- The python tutorial is really great for anyone looking to learn a thing or two about the basics of python. I'd highly recommend you check it out. Here is the section on functions: https://docs.python.org/2/tutorial/controlflow.html#defining-functions...
作为旁注——python 教程非常适合任何想要学习一两件事关于 python 基础知识的人。我强烈建议你检查一下。这是关于函数的部分：https: //docs.python.org/2/tutorial/controlflow.html#defining-functions...
回答by Shanu Pandit
You can simply store the value of random.random()as you are doing to store in a, and after that you may return the value
您可以像存储在 a 中一样简单地存储random.random()的值，然后您可以返回该值
import random
def randombb():
a = random.random()
print(a)
return a
x= randombb()
print(x)
回答by sameera sy
You can make it a global variable if you don't want to return it. Try something like this
如果您不想返回它，可以将其设为全局变量。尝试这样的事情
a = 0 #any value of your choice
def setavalue():
global a # need to declare when you want to change the value
a = random.random()
def printavalue():
print a # when reading no need to declare
setavalue()
printavalue()
print a
