使用 JSONPATH 解析 JSON 数组文件
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Parse JSON array file with JSONPATH
提问by Kheiri Selmi
I want to parse this with JSONPath:
我想用 JSONPath 解析这个：
[
[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
]
Can you help with that please?
你能帮忙吗？
回答by ArjunShankar
If the object is:
如果对象是：
[
[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
]
Then "$[0]"will return:
然后"$[0]"会返回：
[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]
And "$[1]"will return:
而"$[1]"将返回：
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
You can do it two levels deep as well. "$[0][4]"will return:
你也可以做两层深。"$[0][4]"将返回：
205
You can also extract the elements of the array into a list with "$[*]", which will return a list of 2 elements. The first being:
您还可以使用 将数组的元素提取到一个列表中"$[*]"，这将返回一个包含 2 个元素的列表。第一个是：
[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]
and the second being:
第二个是：
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
回答by Hakan Bilgin
Using DefiantJS, you can search a JSON structure with XPath syntax. This library extends the global object JSON with a search function.
使用 DefiantJS，您可以使用 XPath 语法搜索 JSON 结构。该库使用搜索功能扩展了全局对象 JSON。
In this scenario, you can write something like this;
在这种情况下，您可以这样写；
var data = [
[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
],
search = JSON.search( data, '//*/*/*' );
Check out this fiddle; http://jsfiddle.net/hbi99/5NfeM/
看看这个小提琴；http://jsfiddle.net/hbi99/5NfeM/
回答by Jayen Chondigara
This works for me
这对我有用
JsonPath.with(jsonResponse).param("name", "getName").get("findAll { a -> a.name == name }")
