Python：获取实例化类的名称？
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Python: Get name of instantiating class?
提问by Chuck
Example:
例子：
class Class1:
def __init__(self):
self.x = Class2('Woo!')
class Class2:
def __init__(self, word):
print word
meow = Class1()
How do I derive the class name that created the self.x instance? In other words, if I was given the instance self.x, how do I get the name 'Class1'? Using self.x.__class__.__name__will obviously only give you the Class2 name. Is this even possible? Thanks.
如何派生创建 self.x 实例的类名？换句话说，如果给我实例 self.x，我如何获得名称“Class1”？使用self.x.__class__.__name__显然只会给你 Class2 名称。这甚至可能吗？谢谢。
采纳答案by workmad3
You can't, unless you pass an instance of the 'creator' to the Class2() constructor. e.g.
您不能，除非您将“创建者”的实例传递给 Class2() 构造函数。例如
class Class1(object):
def __init__(self, *args, **kw):
self.x = Class2("Woo!", self)
class Class2(object):
def __init__(self, word, creator, *args, **kw):
self._creator = creator
print word
This creates an inverse link between the classes for you
这会为您创建类之间的反向链接
回答by Paul McMillan
Set a variable on the class in question in your __init__()method that you then retrieve later on.
在您的__init__()方法中为相关类设置一个变量，然后您可以稍后检索。
You'll get better answers if you ask better questions. This one is pretty unclear.
如果你提出更好的问题，你会得到更好的答案。这个很不清楚。
