C++ 使用迭代器遍历列表？
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Traverse a List Using an Iterator?
提问by karthik
I need sample for traversing a list using C++.
我需要使用 C++ 遍历列表的示例。
回答by karthik
The sample for your problem is as follows
您的问题的示例如下
#include <iostream>
#include <list>
using namespace std;
typedef list<int> IntegerList;
int main()
{
IntegerList intList;
for (int i = 1; i <= 10; ++i)
intList.push_back(i * 2);
for (IntegerList::const_iterator ci = intList.begin(); ci != intList.end(); ++ci)
cout << *ci << " ";
return 0;
}
回答by Pavel P
To reflect new additions in C++ and extend somewhat outdated solution by @karthik, starting from C++11 it can be done shorterwith autospecifier:
为了反映 C++ 中的新增内容并扩展@karthik 有点过时的解决方案，从 C++11 开始，它可以使用auto说明符缩短：
#include <iostream>
#include <list>
using namespace std;
typedef list<int> IntegerList;
int main()
{
IntegerList intList;
for (int i=1; i<=10; ++i)
intList.push_back(i * 2);
for (auto ci = intList.begin(); ci != intList.end(); ++ci)
cout << *ci << " ";
}
or even easierusing range-based for loops:
或者更容易使用for循环基于范围的：
#include <iostream>
#include <list>
using namespace std;
typedef list<int> IntegerList;
int main()
{
IntegerList intList;
for (int i=1; i<=10; ++i)
intList.push_back(i * 2);
for (int i : intList)
cout << i << " ";
}
回答by Oliver Charlesworth
If you mean an STL std::list, then here is a simple example from http://www.cplusplus.com/reference/stl/list/begin/.
如果您的意思是 STL std::list，那么这里有一个来自http://www.cplusplus.com/reference/stl/list/begin/的简单示例。
// list::begin
#include <iostream>
#include <list>
int main ()
{
int myints[] = {75,23,65,42,13};
std::list<int> mylist (myints,myints+5);
std::cout << "mylist contains:";
for (std::list<int>::iterator it=mylist.begin(); it != mylist.end(); ++it)
std::cout << ' ' << *it;
std::cout << '\n';
return 0;
}
