Oracle 的备用模式中的外键?

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时间:2020-09-19 01:05:01  来源:igfitidea点击:

Foreign keys in alternate schemas with Oracle?

oracleforeign-keys

提问by Skulmuk

I have two schemas, let's call them BOB and FRED. I need to call a table in schema FRED from schema BOB to use the primary key in that table as a foreign key. I've set up the appropriate grants for schema FRED to allow BOB access to it, but whenever I run the script, it complains that I do not have the correct permissions. Is there another setting that I need to change somewhere? Can this even be done?

我有两个模式,我们称它们为 BOB 和 FRED。我需要从架构 BOB 调用架构 FRED 中的表,以将该表中的主键用作外键。我已经为架构 FRED 设置了适当的授权以允许 BOB 访问它,但是每当我运行脚本时,它都会抱怨我没有正确的权限。我需要在某处更改其他设置吗?这甚至可以做到吗?

My FK creation is as follows:

我的FK创作如下:

ALTER TABLE "BOB"."ITEMGROUP" WITH CHECK ADD CONSTRAINT FK_ITEMS_ITEM FOREIGN KEY (ItemID)
REFERENCES "FRED"."ITEMS"(ItemID)

And I'm doing the grant with:

我正在做赠款:

GRANT ALTER ON "FRED"."ITEMS" TO "BOB"

I get this error message:

我收到此错误消息:

SQL Error: ORA-01031: insufficient privileges 
01031. 00000 -  "insufficient privileges"

*Cause:    An attempt was made to change the current username or password
           without the appropriate privilege. This error also occurs if
           attempting to install a database without the necessary operating
           system privileges.
           When Trusted Oracle is configure in DBMS MAC, this error may occur
           if the user was granted the necessary privilege at a higher label
           than the current login.

*Action:   Ask the database administrator to perform the operation or grant
           the required privileges.
           For Trusted Oracle users getting this error although granted the
           the appropriate privilege at a higher label, ask the database
           administrator to regrant the privilege at the appropriate label.

回答by A.B.Cade

You need to:

你需要:

grant references on "FRED"."ITEMS" TO "BOB"

See this"AskTom"

看到这个“AskTom”

回答by Tony Andrews

To create a foreign key referencing a table in another schema you need the "REFERENCES" privilege:

要创建引用另一个模式中的表的外键,您需要“REFERENCES”权限:

GRANT REFERENCES ON FRED.ITEMS TO BOB;