C语言 将矩阵作为函数中的参数传递
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Passing matrix as a parameter in function
提问by user2714823
I have been trying to write a function which gives the index of rows and columns whoses element is 0. I tried using a function
我一直在尝试编写一个函数，它给出元素为 0 的行和列的索引。我尝试使用一个函数
void make_zero(int matrix[][],int row,int col)
{
int row, col;
int i,j;
for(i=0;i<row;i++)
{
for(j=0;j<col;j++)
{
if(matrix[i][j]==0){
printf("%d %d\n", i, j);
}
}
}
But at the time of compiling it gives an error"error: array type has incomplete element type". I also tried declaring the matrix globally and giving it a pointer. But it doesn't work for me. Help me out with this how can we pass matrix to a function in C.
但是在编译时它给出了一个错误“错误：数组类型具有不完整的元素类型”。我还尝试全局声明矩阵并给它一个指针。但这对我不起作用。帮我解决这个问题，我们如何将矩阵传递给 C 中的函数。
采纳答案by haccks
Try this
尝试这个
void make_zero(int row, int col, int matrix[row][col])
{
int i,j;
for(i=0;i<row;i++)
for(j=0;j<col;j++)
{
if(matrix[i][j]==0)
printf("%d %d\n",i,j);
}
}
回答by Sergey L.
Your problem is that multi-dimensional arrays in C need to have their lengths known except for the outermost value.
你的问题是 C 中的多维数组需要知道它们的长度，除了最外面的值。
What you can do is pass the pointer to the memory holding the matrix and then cast it to the right type:
您可以做的是将指针传递给保存矩阵的内存，然后将其转换为正确的类型：
void make_zero(void* _matrix,int row,int col)
{
int i,j;
int (*matrix)[col] = _matrix;
for(i=0;i<row;i++)
for(j=0;j<col;j++)
{
if(matrix[i][j]==0){
printf("%d %d\n",i,j);
}
}
}
回答by Gangadhar
Assuming if you declare int matrix[10][10];like this
假设如果你声明int matrix[10][10];这样
make_zero(matrix,5,5); //function call
void make_zero(int mat[][10],int row,int col) //definition
{
//statements
}
EDIT:
编辑：
the above solution works as long as the actual array passed always has a second dimension of 10 You can use like this As @Jonathan Leffler suggested
只要传递的实际数组的第二维始终为 10，上述解决方案就可以工作，您可以像这样使用@Jonathan Leffler 建议
make_zero(5,5,matrix); //function call
void make_zero(int row, int col, int matrix[row][col]) //definition
{
//statements
}
回答by 42n4
Matrix as argument to a function in C
I have made an "ultimate" solution to this problem in gcc C11/C99 using these links:
我使用以下链接在 gcc C11/C99 中针对此问题提出了“终极”解决方案：
http://c-faq.com/aryptr/dynmuldimary.html
http://c-faq.com/aryptr/dynmuldimary.html
