如何在 JAVA 中对 JSONArray 进行排序
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时间：2020-08-12 18:14:25 来源:igfitidea点击:
How can I sort a JSONArray in JAVA
提问by kumarhimanshu449
How to sort a JSONArray of objects by object's field?
如何按对象的字段对对象的 JSONArray 进行排序？
Input:
输入：
[
{ "ID": "135", "Name": "Fargo Chan" },
{ "ID": "432", "Name": "Aaron Luke" },
{ "ID": "252", "Name": "Dilip Singh" }
];
Desired output (sorted by "Name" field):
所需的输出（按“名称”字段排序）：
[
{ "ID": "432", "Name": "Aaron Luke" },
{ "ID": "252", "Name": "Dilip Singh" }
{ "ID": "135", "Name": "Fargo Chan" },
];
采纳答案by Vito Gentile
Try this:
尝试这个：
//I assume that we need to create a JSONArray object from the following string
String jsonArrStr = "[ { \"ID\": \"135\", \"Name\": \"Fargo Chan\" },{ \"ID\": \"432\", \"Name\": \"Aaron Luke\" },{ \"ID\": \"252\", \"Name\": \"Dilip Singh\" }]";
JSONArray jsonArr = new JSONArray(jsonArrStr);
JSONArray sortedJsonArray = new JSONArray();
List<JSONObject> jsonValues = new ArrayList<JSONObject>();
for (int i = 0; i < jsonArr.length(); i++) {
jsonValues.add(jsonArr.getJSONObject(i));
}
Collections.sort( jsonValues, new Comparator<JSONObject>() {
//You can change "Name" with "ID" if you want to sort by ID
private static final String KEY_NAME = "Name";
@Override
public int compare(JSONObject a, JSONObject b) {
String valA = new String();
String valB = new String();
try {
valA = (String) a.get(KEY_NAME);
valB = (String) b.get(KEY_NAME);
}
catch (JSONException e) {
//do something
}
return valA.compareTo(valB);
//if you want to change the sort order, simply use the following:
//return -valA.compareTo(valB);
}
});
for (int i = 0; i < jsonArr.length(); i++) {
sortedJsonArray.put(jsonValues.get(i));
}
The sorted JSONArray is now stored in the sortedJsonArrayobject.
排序后的 JSONArray 现在存储在sortedJsonArray对象中。
