JavaScript - 找出一个数字平均进入另一个数字的次数
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JavaScript - Find out how many times a number goes into another number evenly
提问by user1822824
Is there a simple way to find how many times a number goes into another number evenly in JavaScript?
有没有一种简单的方法可以在 JavaScript 中找到一个数字平均进入另一个数字的次数？
Say 11 divided by 4 --- I know 4 goes into 11 2 times evenly
说 11 除以 4 --- 我知道 4 平均进入 11 2 次
I have this code but I thought there was a simpler way that I maybe forgetting?
我有这个代码，但我认为有一种更简单的方法可能会忘记？
<script>
a = 11;
b = 4;
i = a % b;
i2 = a - i;
solution = i2 / b;
document.write(solution); // 2
</script>
回答by alex
What about...
关于什么...
Math.floor(11 / 4);
If you're wanting to handle negative numbers (thanks Ted Hopp), you could use ~~, |0or any other bitwise trick that will treat its operand as a 32 bit signed integer. Keep in mind, besides this being confusing, it won't handle a number over 32bits.
如果您想处理负数（感谢Ted Hopp），您可以使用~~，|0或任何其他将其操作数视为 32 位有符号整数的按位技巧。请记住，除了这令人困惑之外，它不会处理超过 32 位的数字。
~~(11 / 4);
回答by Ted Hopp
You can use this trick:
你可以使用这个技巧：
(a / b) >> 0
Shifting by 0 truncates the fractional part. This will always round toward 0, which Math.floorwill not do with negative numbers.
移动 0 会截断小数部分。这将始终向 0 舍入，这Math.floor与负数无关。
