Java org.json.simple.JSONArray 不能转换为 org.json.simple.JSONObject

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时间:2020-08-12 01:38:43  来源:igfitidea点击:

org.json.simple.JSONArray cannot be cast to org.json.simple.JSONObject

javajson

提问by tokhi

I'm trying to parse below jsonfile:

我正在尝试解析以下json文件:

{"units":[{"id":42,               
   "title":"Hello World",          
    "position":1,
    "v_id":9,
    "sites":[[{"id":316,
      "article":42,
      "clip":133904
        }],
       {"length":5}]

   }, ..]}

This is what I have tried:

这是我尝试过的:

Object obj = null;
JSONParser parser = new JSONParser();
Object unitsObj = parser.parse(new FileReader("file.json");
JSONObject unitsJson = (JSONObject) unitsObj;

JSONArray units = (JSONArray) unitsJson.get("units");
Iterator<String> unitsIterator = units.iterator();
while(unitsIterator.hasNext()){         
    Object uJson = unitsIterator.next();
    JSONObject uj = (JSONObject) uJson;
    obj =  parser.parse(uj.get("sites").toString());
    JSONArray jsonSites = (JSONArray)  obj;

    for(int i=0;i<jsonSites.size();i++){
     JSONObject site = (JSONObject)jsonSites.get(i); // Exception happens here.
     System.out.println(site.get("article");
    }
}

The code is not working when I try to parse the inner json array, so I get:

当我尝试解析内部代码时,代码不起作用json array,所以我得到:

Exception in thread "main" java.lang.ClassCastException: org.json.simple.JSONArray cannot be cast to org.json.simple.JSONObject

The exception is pointing to this line:

异常指向这一行:

JSONObject site = (JSONObject)jsonSites.get(i);

Any help? tnx.

有什么帮助吗?tnx。

回答by cyberz

The first element of the sitesarray is an array, as you can see indenting the JSON:

sites数组的第一个元素是一个数组,你可以看到缩进 JSON:

{"units":[{"id":42,               
    ...
    "sites":
    [
      [
        {
          "id":316,
          "article":42,
          "clip":133904
        }
      ],
      {"length":5}
    ]
    ...
}

Therefore you need to treat its value accordingly; probably you could do something like:

因此你需要相应地对待它的价值;也许你可以做这样的事情:

JSONObject site = (JSONObject)(((JSONArray)jsonSites.get(i)).get(0));

回答by Onur A.

JSONObject site=jsonSites.getJSONObject(i)should work out

JSONObject site=jsonSites.getJSONObject(i)应该解决

回答by Danon

I've found a working code:

我找到了一个工作代码:

JSONParser parser = new JSONParser();
Object obj  = parser.parse(content);
JSONArray array = new JSONArray();
array.add(obj);

回答by Krishna D

use your jsonsimpleobject direclty like below

像下面一样使用你的 jsonsimpleobject direclty

JSONObject unitsObj = parser.parse(new FileReader("file.json");

回答by Ars

JSONObject obj=(JSONObject)JSONValue.parse(content); 
JSONArray arr=(JSONArray)obj.get("units"); 
System.out.println(arr.get(1));  //this will print {"id":42,...sities ..}

@cyberz is right but explain it reverse

@cyberz 是对的,但反过来解释

回答by arn-arn

this worked:

这有效:

System.out.println("resultList.toString() " + resultList);
            org.json.JSONObject obj = new JSONObject(resultList);
            org.json.JSONArray jsonArray = obj.getJSONArray(someField);

            for(int i=0;i<jsonArray.length();i++){
                System.out.println("array is " + jsonArray.get(i));

            }

回答by LoveToCode

You can first read the whole content of file into a String.

您可以先将文件的全部内容读入一个字符串。

FileInputStream fileInputStream = null;
String data="";
StringBuffer stringBuffer = new StringBuffer("");
try{
    fileInputStream=new FileInputStream(filename);
    int i;
    while((i=fileInputStream.read())!=-1)
    {
        stringBuffer.append((char)i);
    }
    data = stringBuffer.toString();
}
catch(Exception e){
        LoggerUtil.printStackTrace(e);
}
finally{
    if(fileInputStream!=null){  
        fileInputStream.close();
    }
}

Now You will have the whole content into String ( data variable ).

现在您将把整个内容转换为 String (数据变量)。

JSONParser parser = new JSONParser();
org.json.simple.JSONArray jsonArray= (org.json.simple.JSONArray) parser.parse(data);

After that you can use jsonArray as you want.

之后,您可以根据需要使用 jsonArray。

回答by ritesh yadav

JSONObject baseReq
LinkedHashMap insert = (LinkedHashMap) baseReq.get("insert");
LinkedHashMap delete = (LinkedHashMap) baseReq.get("delete");

回答by prasad

If you want to re-filter the json data you can use following method. Given example is getting all document data from couchdb.

如果要重新过滤 json 数据,可以使用以下方法。给定的示例是从 couchdb 获取所有文档数据。

{
    Gson gson = new Gson();
    String resultJson = restTemplate.getForObject(url+"_all_docs?include_docs=true", String.class);
    JSONObject object =  (JSONObject) new JSONParser().parse(resultJson);
    JSONArray rowdata = (JSONArray) object.get("rows");   
    List<Object>list=new ArrayList<Object>();   
    for(int i=0;i<rowdata.size();i++) {
        JSONObject index = (JSONObject) rowdata.get(i);
        JSONObject data = (JSONObject) index.get("doc");
        list.add(data);      
    }
    // convert your list to json
    String devicelist = gson.toJson(list);
    return devicelist;
}

回答by Stacie

JSONObject site = (JSONObject)jsonSites.get(i); // Exception happens here.

The return type of jsonSites.get(i)is JSONArraynot JSONObject. Because sites have two '[', two means there are two arrays here.

的返回类型jsonSites.get(i)JSONArray不是JSONObject。因为站点有两个 '[',两个意味着这里有两个数组。