javascript 设置 cookie 一天后过期

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时间:2020-10-28 16:00:09  来源:igfitidea点击:

Setting cookie to expire after one day

javascriptjquerycookies

提问by user2278240

I have used this code I got from git. Its basically set up to set a cookie to display a popup on the first visit to the site only. However, I want it to only set it for 24 hours. So if someone comes back to the site in a day or two it will show again.

我已经使用了从 git 获得的这段代码。它基本上设置为设置 cookie 以仅在第一次访问该站点时显示弹出窗口。但是,我希望它只设置 24 小时。因此,如果有人在一两天内再次访问该站点,它将再次显示。

(function ($) {

    'use strict';

    $.fn.firstVisitPopup = function (settings) {

        var $body = $('body');
        var $dialog = $(this);
        var $blackout;
        var setCookie = function (name, value) {
            var date = new Date(),
                expires = 'expires=';
            date.setTime(date.getTime() + 31536000000);
            expires += date.toGMTString();
            document.cookie = name + '=' + value + '; ' + expires + '; path=/';
        }
        var getCookie = function (name) {
            var allCookies = document.cookie.split(';'),
                cookieCounter = 0,
                currentCookie = '';
            for (cookieCounter = 0; cookieCounter < allCookies.length; cookieCounter++) {
                currentCookie = allCookies[cookieCounter];
                while (currentCookie.charAt(0) === ' ') {
                    currentCookie = currentCookie.substring(1, currentCookie.length);
                }
                if (currentCookie.indexOf(name + '=') === 0) {
                    return currentCookie.substring(name.length + 1, currentCookie.length);
                }
            }
            return false;
        }
        var showMessage = function () {
            $blackout.show();
            $dialog.show();
        }
        var hideMessage = function () {
            $blackout.hide();
            $dialog.hide();
            setCookie('fvpp' + settings.cookieName, 'true');
        }

        $body.append('<div id="fvpp-blackout"></div>');
        $dialog.append('<a id="fvpp-close">&#10006;</a>');
        $blackout = $('#fvpp-blackout');

        if (getCookie('fvpp' + settings.cookieName)) {
            hideMessage();
        } else {
            showMessage();
        }

        $(settings.showAgainSelector).on('click', showMessage);
        $body.on('click', '#fvpp-blackout, #fvpp-close', hideMessage);

    };

})(jQuery);

回答by Barmar

Change:

改变:

date.setTime(date.getTime() + 31536000000);

to:

到:

date.setDate(date.getDate() + 1);

This adds 1 day to the date. The old code was adding 365 days.

这将在日期上增加 1 天。旧代码增加了 365 天。

回答by abo46n2

This is what I do in my projects which I find easier to understand. Just change the last number according to how many days you want to add to the current time, timestamp:

这就是我在我的项目中所做的,我觉得这更容易理解。只需根据您要添加到当前时间的天数更改最后一个数字,即可timestamp

const timestamp = new Date().getTime(); // current time
const exp = timestamp + (60 * 60 * 24 * 1000 * 7)

60 minutes * 60 seconds * 24 hours * 1000 (for milliseconds) * 7 days

60分钟*60秒*24小时*1000(毫秒)*7天

or you could simply use 86400000.

或者你可以简单地使用86400000.