从 Windows 批处理文件替换文本文件中的字符
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原文地址: http://stackoverflow.com/questions/42482508/
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Replacing characters in a text file from Windows batch file
提问by Wally Walters
I'm trying to write a batch file that will look at every character in a small text file (a CUE sheet, actually) and do three things -- remove all question marks, replace any slash marks with a hyphen and replace colons with two hyphens -- as per the second line in the example below.
我正在尝试编写一个批处理文件，该文件将查看小文本文件（实际上是 CUE 表）中的每个字符，并执行三件事——删除所有问号，用连字符替换任何斜杠，用两个替换冒号连字符 - 根据下面示例中的第二行。
TRACK 01 AUDIO
TITLE "Colon: Slash / Question Mark?"
(would be changed to)
TITLE "Colon -- Slash - Question Mark"
I know how to use findstr to copy the lines containing those characters to a new text file (but only those lines), and not how to do the search-and-replace. And findstr also has the unwanted consequence of removing leading spaces, which I wish to retain. Not sure what's the right approach here. (I should add that for various reasons I prefer not to use a third-party utility.)
我知道如何使用 findstr 将包含这些字符的行复制到一个新的文本文件（但仅限于那些行），而不是如何进行搜索和替换。而且 findstr 还具有删除前导空格的不良后果，我希望保留这些空格。不确定这里的正确方法是什么。（我应该补充一点，出于各种原因，我不喜欢使用第三方实用程序。）
回答by Baljeetsingh
You can use Powershell to solve this very easily.
您可以使用 Powershell 非常轻松地解决此问题。
Open PowerShell and type this
打开PowerShell并输入
(Get-Content C:\Users\Admin\StackOverflow\some.txt).Replace(":"," - -") | Set-Content C:\Users\Admin\StackOverflow\SomeModified.txt
Basically,
基本上，
Get-Contentwill open the file.
Get-Content将打开文件。
.Replaceto replace the text(old text, new text)
.Replace替换文本（旧文本、新文本）
| Set-Content< path > to output on diffrent file.
| 设置内容<路径> 以在不同的文件上输出。
Screenshots
截图
回答by Magoo
@ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
SET "sourcedir=U:\sourcedir"
SET "destdir=U:\destdir"
SET "filename1=%sourcedir%\q42482508.txt"
SET "outfile=%destdir%\outfile.txt"
(
FOR /f "usebackqdelims=" %%a IN ("%filename1%") DO (
SET "line=%%a"
SET "line=!line:?=!"
SET "line=!line:/=-!"
SET "line=!line::=--!"
ECHO !line!
)
)>"%outfile%"
GOTO :EOF
You would need to change the settings of sourcedirand destdirto suit your circumstances.
您需要更改的设置sourcedir，并destdir以适合你的情况。
I used a file named q42482508.txtcontaining your data for my testing.
我使用了一个名为q42482508.txt包含您的数据的文件进行测试。
Produces the file defined as %outfile%
生成定义为 %outfile% 的文件
Invoke delayed expansion to allow strings to be manipulated in a code block.
调用延迟扩展以允许在代码块中操作字符串。
Read each line of the file to %%athence line; replace each ?with nothing, /with one -and :with two, and echothe result.
读取文件的每一行到%%a那里line；替换每个?有没有，/有一个-和:两个，和echo结果。
Parenthesising the forallows redirection to the specified file.
括号for允许重定向到指定的文件。
The pattern is set "var1=!var2:stringtoreplace=replacementstring!" as documented, !in place of %to use delayedexpansion.
模式设置为 "var1=!var2: stringtoreplace= replacementstring!" 如文档所述，!代替%使用延迟扩展。
Note that your text specifies the replacemnt string for :as --whereas your example shows it being replaced by "Space--"
请注意，您的文本指定了替换字符串:as--而您的示例显示它被替换为“ Space--”
