java 如何从静态 main() 方法调用内部类的方法
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how to call inner class's method from static main() method
提问by sunny_dev
Trying to create 1 interface and 2 concrete classes inside a Parent class. This will qualify the enclosing classes to be Inner classes.
试图在父类中创建 1 个接口和 2 个具体类。这将使封闭类成为内部类。
public class Test2 {
interface A{
public void call();
}
class B implements A{
public void call(){
System.out.println("inside class B");
}
}
class C extends B implements A{
public void call(){
super.call();
}
}
public static void main(String[] args) {
A a = new C();
a.call();
}
}
Now I am not really sure how to create the object of class C inside the static main() method and call class C's call() method.
Right now I am getting problem in the line : A a = new C();
现在我不太确定如何在静态 main() 方法中创建类 C 的对象并调用类 C 的 call() 方法。现在我遇到了问题： A a = new C();
回答by Qiang Jin
Here the inner class is not static, so you need to create an instance of outer class and then invoke new,
这里的内部类不是静态的，所以需要先创建一个外部类的实例，然后再调用new，
A a = new Test2().new C();
But in this case, you can make the inner class static,
但是在这种情况下，您可以将内部类设为静态，
static class C extends B implements A
then it's ok to use,
然后就可以使用了
A a = new C()
回答by NINCOMPOOP
To instantiate an inner class, you must first instantiate the outer class. Then, create the inner object within the outer object with this syntax:
要实例化内部类，必须先实例化外部类。然后，使用以下语法在外部对象中创建内部对象：
OuterClass.InnerClass innerObject = outerObject.new InnerClass();
So you need to use :
所以你需要使用：
A a = new Test2().new C();
Refer the Java Tutorial.
请参阅Java 教程。
回答by oks16
You should do this
你应该做这个
A a = new Test2().new C();
