JavaScript 函数可以返回自身吗？
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Can a JavaScript function return itself?
提问by fbas
Can I write a function that returns iteself?
我可以编写一个返回 itself 的函数吗？
I was reading some description on closures - see Example 6- where a function was returning a function, so you could call func()();as valid JavaScript.
我正在阅读一些关于闭包的描述——参见示例 6——其中一个函数正在返回一个函数，因此您可以func()();作为有效的 JavaScript调用。
So I was wondering could a function return itself in such a way that you could chain it to itself indefinitely like this:
所以我想知道一个函数是否可以以这样的方式返回自己，你可以像这样无限期地将它链接到自己：
func(arg)(other_arg)()(blah);
Using argumentsobject, callee or caller?
使用arguments对象、被调用者还是调用者？
回答by Flambino
There are 2-3 ways. One is, as you say, is to use arguments.callee. It might be the only way if you're dealing with an anonymous function that's not stored assigned to a variable somewhere (that you know of):
有2-3种方式。一种是，正如你所说，是使用arguments.callee. 如果您正在处理未存储分配给某个变量的匿名函数（您知道），这可能是唯一的方法：
(function() {
return arguments.callee;
})()()()().... ;
The 2nd is to use the function's name
第二种是使用函数名
function namedFunc() {
return namedFunc;
}
namedFunc()()()().... ;
And the last one is to use an anonymous function assigned to a variable, but you have to know the variable, so in that case I see no reason, why you can't just give the function a name, and use the method above
最后一个是使用匿名函数赋值给一个变量，但是你必须知道这个变量，所以在那种情况下我看不出有什么理由，为什么你不能只给函数一个名字，并使用上面的方法
var storedFunc = function() {
return storedFunc;
};
storedFunc()()()().... ;
They're all functionally identical, but calleeis the simplest.
它们在功能上都相同，但callee最简单。
Edit: And I agree with SLaks; I can't recommend it either
编辑：我同意 SLaks；我也不能推荐
回答by SLaks
Yes.
Just return arguments.callee;
是的。
只是return arguments.callee;
However, this is likely to result in very confusing code; I do not recommend it.
然而，这很可能会导致非常混乱的代码；我不推荐它。
回答by ataru
You can do what you want as following:
您可以执行以下操作：
// Do definition and execution at the same time.
var someFunction = (function someFunction() {
// do stuff
return someFunction
})();
console.log(someFunction)
arguments.calleeis not supported in JavaScript strict mode.
JavaScript 严格模式不支持arguments.callee。
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Strict_mode
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Strict_mode
回答by ??? ?
Even sorter that all the above is:
甚至分拣机以上所有内容是：
f=()=>f回答by zero_cool
There is a simple way to achieve this doing the following:
有一个简单的方法来实现这一点，请执行以下操作：
let intArr = [];
function mul(x){
if(!x){
return intArr.reduce((prev, curr) => prev * curr)
}
intArr.push(x);
return mul;
}
console.log(mul(2)(4)(2)()); => outputs 16
回答by konstantin555
It is also possible just to return the argument the self invokable function like
也可以只返回自调用函数的参数，如
console.log( (function(a) { return a; })(1) ); // returns 1
