Python Matplotlib 散点标记大小
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Matplotlib scatter marker size
提问by PerroNoob
I'm trying to plot a 3D scatter with matplotlibThe problem is that I can't change the marker's size
I have this
我正在尝试绘制 3D 散点图matplotlib问题是我无法更改标记的大小我有这个
scat = plt.scatter([boid_.pos[0] for boid_ in flock],
[boid_.pos[1] for boid_ in flock],
[boid_.pos[2] for boid_ in flock],
marker='o', s=5)
But I get the error
但我得到了错误
TypeError: scatter() got multiple values for keyword argument 's'
Without that, the plot works fine. Where is the problem? Or is there another way to change the size?
没有那个，情节运作良好。问题出在哪儿？或者有其他方法可以改变大小吗？
采纳答案by wim
This function takes in two args before the keyword args:
此函数在关键字 args 之前接受两个 args：
scatter(x, y, s=20, ...)
scatter(x, y, s=20, ...)
And you are passing in three, so you are specifying stwice (once implicitly and once explicitly).
并且您传入了三个，因此您指定了s两次（一次隐式，一次显式）。
Actually, I think you are trying to use the 2D scatter plot function instead of a 3D one. You probably want to do this instead:
实际上，我认为您正在尝试使用 2D 散点图函数而不是 3D 散点图函数。你可能想这样做：
from mpl_toolkits.mplot3d import Axes3D
Axes3D.scatter( ... )
