python Python中的一小时差异
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/2571432/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
One hour difference in Python
提问by Joel
I have a datetime.datetime property var. I would like to know if it is less than one hour of the current time. Something like
我有一个 datetime.datetime 属性变量。我想知道它是否小于当前时间的一小时。就像是
var.hour<datetime.datetime.today().hour - 1
Problem with the above syntax is that
上述语法的问题在于
datetime.datetime.today().hour
returns a number such as "10" and it is not really a date comparation but more of a numbers comparation.
返回一个数字，例如“10”，它实际上不是日期比较，而是更多的数字比较。
What is the correct syntax?
什么是正确的语法？
Thanks!
谢谢！
Joel
乔尔
回答by Daniel Roseman
Use datetime.timedelta.
使用datetime.timedelta.
var < datetime.datetime.today() - datetime.timedelta(hours=1)
回答by pocoa
You can use dateutil.relativedelta
from datetime import datetime, timedelta
from dateutil.relativedelta import relativedelta
now = datetime.now()
other_time = now + timedelta(hours=8)
diff = relativedelta(other_time, now)
print diff.hours # 8
