C# 将字符串转换为类名
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Converting a string to a class name
提问by Bob Smith
I have a string variable that represents the name of a custom class. Example:
我有一个表示自定义类名称的字符串变量。例子：
string s = "Customer";
I will need to create an arraylist of customers. So, the syntax needed is:
我需要创建一个客户数组列表。所以，需要的语法是：
List<Customer> cust = new ..
How do I convert the string s to be able to create this arraylist on runtime?
如何转换字符串 s 以便能够在运行时创建此数组列表？
采纳答案by Jon Skeet
Well, for one thing ArrayListisn't generic... did you mean List<Customer>?
嗯，一方面ArrayList不是通用的……你的意思是List<Customer>？
You can use Type.GetType(string)to get the Typeobject associated with a type by its name. If the assembly isn't either mscorlib or the currently executing type, you'll need to include the assembly name. Either way you'll need the namespace too.
您可以使用它的名称Type.GetType(string)来获取Type与类型关联的对象。如果程序集不是 mscorlib 或当前正在执行的类型，则需要包含程序集名称。无论哪种方式，您都需要命名空间。
Are you sure you really need a generic type? Generics mostly provide compile-timetype safety, which clearly you won't have much of if you're finding the type at execution time. You mayfind it useful though...
你确定你真的需要一个泛型类型吗？泛型主要提供编译时类型安全，如果您在执行时找到类型，显然不会有太多的类型安全。你可能会发现它很有用...
Type elementType = Type.GetType("FullyQualifiedName.Of.Customer");
Type listType = typeof(List<>).MakeGenericType(new Type[] { elementType });
object list = Activator.CreateInstance(listType);
If you need to doanything with that list, you may well need to do more generic reflection though... e.g. to call a generic method.
如果你需要对这个列表做任何事情，你可能需要做更多的通用反射……例如调用通用方法。
回答by pezi_pink_squirrel
This is a reflection question. You need to find the type then instantiate an instance of it, something like this:
这是一道反思题。您需要找到类型，然后实例化它的一个实例，如下所示：
Type hai = Type.GetType(classString,true);
Object o = (Activator.CreateInstance(hai)); //Or you could cast here if you already knew the type somehow
or, CreateInstance(assemblyName, className)
或者， CreateInstance(assemblyName, className)
You will need to watch out for namespace/type clashes though, but that will do the trick for a simple scenario.
不过，您需要注意命名空间/类型冲突，但这对于一个简单的场景就可以解决问题。
Also, wrap that in a try/catch! Activator.CreateInstance is scary!
另外，将其包装在 try/catch 中！Activator.CreateInstance 是可怕的！
