仅在 Android 软键盘上显示数字按钮？
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Only show number buttons on Soft Keyboard in Android?
提问by Benny Skogberg
On the soft keyboard in Android you can set the soft keyboard to show the numbers instead of a-z keyboard using android:inputType="numberDecimal". However, what do I do if I only want to show the top number row 1 2 3 4 5 6 7 8 9 0and not the following rows starting with @ # $ % ...?
在 Android 的软键盘上，您可以使用 将软键盘设置为显示数字而不是 az 键盘android:inputType="numberDecimal"。但是，如果我只想显示顶部数字行1 2 3 4 5 6 7 8 9 0而不是以 开头的以下行，我该怎么办@ # $ % ...？
Thanx for listening!
感谢聆听！
回答by softarn
android:inputType="phone"
android:digits="1234567890"
is an option
是一种选择
回答by sergidk
You must only add this line on your code:
您只能在代码中添加这一行：
input.setRawInputType(Configuration.KEYBOARD_12KEY);
this will show onlythe numeric keyboard.
这将仅显示数字键盘。
回答by Justin
The phone number pad is the closest thing I've found (set inputType="phone"on your EditText).
电话号码板是我找到的最接近的东西（设置inputType="phone"在你的EditText）。
回答by PDP
The accepted answer did not work for me (tested on OnePlus 3t and Samsung Galaxy S6/S7 phones).
接受的答案对我不起作用（在 OnePlus 3t 和三星 Galaxy S6/S7 手机上测试）。
This solution uses numberPassword but overrides the default transformation method for the EditText to show characters instead of showing dots.
此解决方案使用 numberPassword 但覆盖 EditText 的默认转换方法以显示字符而不是显示点。
<EditText
android:id="@+id/userid"
android:inputType="numberPassword"
android:maxLength="6"
/>
// Numeric 6 character user id
EditText input = findViewById(R.id.userid);
// Process input and show characters instead of dots
input.setTransformationMethod(SingleLineTransformationMethod.getInstance());
回答by TopherC
Just posted an answer herebut re-posting for simplicity:
Seems Android has added the functionality we were seeking. This is the xml I use for simple EditText numeric entry:
似乎 Android 已经添加了我们正在寻求的功能。这是我用于简单 EditText 数字条目的 xml：
android:inputType="numberPassword"
android:digits="0123456789"
android:singleLine="true"
android:ems="4"
android:textColor="@android:color/black"
android:gravity="center"
回答by Spike Williams
Last I looked into it, Android did not have any good options for that. I ended up having to write my own version of a soft keyboard-like user interface.
最后我研究了一下，Android 没有任何好的选择。我最终不得不编写自己的类似软键盘的用户界面版本。
回答by Altaf Virani
I had implemented this for android in Xamarin. So, my code is in C#. But the principal stays the same. You can set attribute of edittext to android:inputType="numberPassword".
我已经在 Xamarin 中为 android 实现了这个。所以，我的代码是在 C# 中。但校长保持不变。您可以将 edittext 的属性设置为android:inputType="numberPassword".
Then within your code you attach custom transformation method to your edittext view.
然后在您的代码中，您将自定义转换方法附加到您的 edittext 视图。
holder.edtxtQty.TransformationMethod = new HiddenPasswordTransformationMethod();
private class HiddenPasswordTransformationMethod : global::Android.Text.Method.PasswordTransformationMethod
{
public override Java.Lang.ICharSequence GetTransformationFormatted(Java.Lang.ICharSequence source, View view)
{
return new PasswordCharSequence(source);
}
}
private class PasswordCharSequence : Java.Lang.Object, Java.Lang.ICharSequence
{
private char DOT = '\u2022';
private Java.Lang.ICharSequence _source;
public PasswordCharSequence(Java.Lang.ICharSequence source)
{
_source = source;
}
public char CharAt(int index)
{
return _source.CharAt(index);
}
public int Length()
{
return _source.Length();
}
public Java.Lang.ICharSequence SubSequenceFormatted(int start, int end)
{
return _source.SubSequenceFormatted(start, end); // Return default
}
public IEnumerator<char> GetEnumerator()
{
return _source.GetEnumerator();
}
System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
{
return _source.GetEnumerator();
}
}
回答by sgc_code
The accepted answer didn't work for me. It kept showing other unwanted characters
接受的答案对我不起作用。它一直显示其他不需要的字符
I found a way to accomplish the behavior I wanted by changing the inputType to numberPasswordand then disabling the password dots
我找到了一种方法来完成我想要的行为，方法是将 inputType 更改为numberPassword然后禁用密码点
textInput.inputType = InputType.TYPE_CLASS_NUMBER or InputType.TYPE_NUMBER_VARIATION_PASSWORD
textInput.transformationMethod = SingleLineTransformationMethod()
