java 具有多个参数的 MapStruct QualifiedByName
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MapStruct QualifiedByName with multiple parameters
提问by Vivek Gupta
I have come across a situation where my mapping method has 3 parameters, and all the three are being used in deriving one of the properties of the target type.
我遇到过这样一种情况,我的映射方法有 3 个参数,并且所有三个参数都用于派生目标类型的属性之一。
I have created a default mapping method in the interface keeping the logic for deriving the property, now for calling this method, I could use an expression = "java( /*method call here*/ )"
in the @Mapping
annotation.
我在接口中创建了一个默认映射方法,保留派生属性的逻辑,现在为了调用这个方法,我可以expression = "java( /*method call here*/ )"
在@Mapping
注释中使用 an 。
Is there any way to do this with any of the mapstruct annotation like @qualifiedByName
, I tried commenting the annotation having expression property and used qualifiedByName, but it doesn't work :
有什么方法可以使用任何 mapstruct 注释来做到这一点,例如@qualifiedByName
,我尝试评论具有表达式属性的注释并使用了qualifiedByName,但它不起作用:
@Mapper
public interface OneMapper {
@Mapping(target="id", source="one.id")
//@Mapping(target="qualified",expression = "java( checkQualified (one, projId, code) )")
@Mapping(target="qualified",qualifiedByName="checkQualifiedNamed")
OneDto createOne (One one, Integer projId, Integer val, String code);
@Named("checkQualifiedNamed")
default Boolean checkQualified (One one, Integer projId, Integer val, String code) {
if(one.getProjectId() == projId && one.getVal() == val && one.getCode().equalsIgnoreCase(code)) {
return Boolean.TRUE;
}
return Boolean.FALSE;
}
}
回答by Filip
Currently MapStruct does not support mapping methods with multiple source properties.
目前 MapStruct 不支持具有多个源属性的映射方法。
However, in your case you can use the @Context
from 1.2.0. From what I understand the projId
and the code
are there just as helper of the mapping, and they are not used to map target properties from.
但是,在您的情况下,您可以使用@Context
from 1.2.0。据我所知,theprojId
和 thecode
只是映射的助手,它们不用于映射目标属性。
So you can do something like (It should work in theory):
所以你可以做一些类似的事情(理论上应该可以):
@Mapper
public interface OneMapper {
@Mapping(target="id", source="one.id")
@Mapping(target="qualified", qualifiedByName="checkQualifiedNamed")
OneDto createOne (One one, @Context Integer projId, @Context String code);
@Named("checkQualifiedNamed")
default Boolean checkQualified (One one, @Context Integer projId, @Context String code) {
if(one.getProjectId() == projId && one.getCode().equalsIgnoreCase(code)) {
return Boolean.TRUE;
}
return Boolean.FALSE;
}
}
Another alternative would be to extract all those properties into a separate class and pass that along (this would allow for multiple parameters of the same type).
另一种选择是将所有这些属性提取到一个单独的类中并将其传递(这将允许相同类型的多个参数)。
The class would look like:
这个类看起来像:
public class Filter {
private final Integer projId;
private final Integer val;
private final String code;
public Filter (Integer projId, Integer val, String code) {
this.projId = projId;
this.val = val;
this.code = code;
}
//getters
}
Your mapper will then look like:
您的映射器将如下所示:
@Mapper
public interface OneMapper {
@Mapping(target="id", source="one.id")
@Mapping(target="qualified", qualifiedByName="checkQualifiedNamed")
OneDto createOne (One one, @Context Filter filter);
@Named("checkQualifiedNamed")
default Boolean checkQualified (One one, @Context Filter filter) {
if(one.getProjectId() == filter.getProjId() && one.getVal() == filter.getVal() && one.getCode().equalsIgnoreCase(filter.getCode())) {
return Boolean.TRUE;
}
return Boolean.FALSE;
}
}
You can then call the mapper like: mapper.createOne(one, new Filter(projId, val, code));
然后你可以像这样调用映射器: mapper.createOne(one, new Filter(projId, val, code));
回答by Pim Hazebroek
Since version 1.2 it is supported: http://mapstruct.org/documentation/stable/reference/html/#mappings-with-several-source-parameters
从 1.2 版开始支持:http: //mapstruct.org/documentation/stable/reference/html/#mappings-with-several-source-parameters
For example like this:
例如像这样:
@Mappings({
@Mapping(source = "person.description", target = "description"),
@Mapping(source = "address.houseNo", target = "houseNumber")
})
DeliveryAddressDto personAndAddressToDeliveryAddressDto(Person person, Address address);