在Python中的空格处拆分列表中的每个字符串
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Splitting each string in a list at spaces in Python
提问by Arc'
I've got a list that contains a url and some text in each item of a large list in Python. I'd like to split each item in several items every time a space appears (2-3 spaces per item). There isn't much code to post, its just a list stored in a named variable at the moment. I've tried using the split function but I just can't seem to get it right. Any help would be greatly appreciated!
我有一个列表，其中包含一个 url 和 Python 中大型列表的每个项目中的一些文本。每次出现空格时，我想将每个项目拆分为多个项目（每个项目 2-3 个空格）。没有太多代码要发布，它只是目前存储在命名变量中的列表。我试过使用 split 功能，但我似乎无法正确使用。任何帮助将不胜感激！
回答by ank
You can try something like that:
你可以尝试这样的事情：
>>> items = ['foo bar', 'baz', 'bak foo bar']
>>> new_items = []
>>> for item in items:
... new_items.extend(item.split())
...
>>> new_items
['foo', 'bar', 'baz', 'bak', 'foo', 'bar']
回答by Mark Ransom
It's hard to know what you're asking for but I'll give it a shot.
很难知道你在要求什么，但我会试一试。
>>> a = ['this is', 'a', 'list with spaces']
>>> [words for segments in a for words in segments.split()]
['this', 'is', 'a', 'list', 'with', 'spaces']
