Javascript 使用javascript获取两个字符串之间的字符串
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/27656575/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
get string between two strings with javascript
提问by user3080392
How do I get a string between two strings using match with variables? The following code works well if I use match with strings Regular Expression to get a string between two strings in JavascriptI also tried to apply the info at JavaScript - Use variable in string match:
如何使用变量匹配在两个字符串之间获取字符串？如果我使用匹配字符串正则表达式来获取 Javascript 中两个字符串之间的字符串，以下代码运行良好，我还尝试在JavaScript 中应用信息- 在字符串匹配中使用变量：
var test = "My cow always gives milk";
var testRE = test.match("cow(.*)milk");
alert(testRE[1]);
But what if I have:
但是如果我有：
var firstvariable = "cow";
var secondvariable = "milk";
var test = "My cow always gives milk";
I've tried various things including:
我尝试了各种方法，包括：
var testRE = test.match("firstvariable(.*)secondvariable");
alert(testRE[1]);
and:
和：
var testRE = testRE.match + '("' + firstvariable + "(.*)" + secondvariable +'")';
alert(testRE[1]);
Neither worked.
都没有工作。
回答by myTerminal
Try this:
尝试这个：
test.match(new RegExp(firstvariable + "(.*)" + secondvariable));
回答by Mouser
Use this code
使用此代码
var regExString = new RegExp("(?:"+firstvariable+")((.[\s\S]*))(?:"+secondvariable+")", "ig"); //set ig flag for global search and case insensitive
var testRE = regExString.exec("My cow always gives milk.");
if (testRE && testRE.length > 1) //RegEx has found something and has more than one entry.
{
alert(testRE[1]); //is the matched group if found
}
This matches only the middle part of the sentence.
这仅匹配句子的中间部分。
(?:"+firstvariable+")finds but does not capturecow.(.*?)captures all characters betweencowandmilkand saves it in a group.?makes it lazy so it stops at milk.(?:"+secondvariable+")finds but does not capturemilk.
(?:"+firstvariable+")找到但不捕获cow.(.*?)捕获所有字符之间cow，并milk和一组保存它。?让它变得懒惰，所以它停在牛奶上。(?:"+secondvariable+")找到但不捕获milk.
You can test this below:
您可以在下面进行测试：
function testString()
{
var test = document.getElementById("testStringDiv").textContent;
var firstvariable = document.querySelectorAll("input")[0].value; //first input;
var secondvariable = document.querySelectorAll("input")[1].value; //second input;
var regExString = new RegExp("(?:"+firstvariable+")((.[\s\S]*))(?:"+secondvariable+")", "ig");
var testRE = regExString.exec(test);
if (testRE && testRE.length > 1)
{
document.getElementById("showcase").textContent = testRE[1]; //return second result.
}
}
document.getElementById("test").addEventListener("click", testString, true);<div id="testStringDiv">My cow always gives milk.</div>
<div id="showcase">Result will display here...</div>
<input placeholder="enter first var"/><input placeholder="enter second var"/><button id="test">Search in between...</button>