简单的冒泡排序 C#

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时间:2020-08-10 12:56:39  来源:igfitidea点击:

Simple bubble sort c#

c#arrayssortingbubble-sort

提问by Karim O.

int[] arr = {800,11,50,771,649,770,240, 9};

int temp = 0;

for (int write = 0; write < arr.Length; write++)
{
    for (int sort = 0; sort < arr.Length - 1; sort++)
    {
        if (arr[sort] > arr[sort + 1])
        {
            temp = arr[sort + 1];
            arr[sort + 1] = arr[sort];
            arr[sort] = temp;
        }       
    }   
    Console.Write("{0} ", arr[write]);  
}

All I am attempting to do is a simple bubble sort with this array. I would like to figure out why the sorting is screwed up. In example, here is when the array is {800,11,50,771,649,770,240, 9}:

我试图做的只是对这个数组进行简单的冒泡排序。我想弄清楚为什么排序会搞砸。例如,这里是数组时{800,11,50,771,649,770,240, 9}

Here is what gets displayed: 11, 50, 649, 9, 649, 770, 771, 800

这是显示的内容: 11, 50, 649, 9, 649, 770, 771, 800

I am thinking that I might be missing something in the comparison.

我想我可能会在比较中遗漏一些东西。

采纳答案by Matten

No, your algorithm works but your Writeoperation is misplaced within the outer loop.

不,您的算法有效,但您的Write操作在外循环中放错了位置。

int[] arr = { 800, 11, 50, 771, 649, 770, 240, 9 };

int temp = 0;

for (int write = 0; write < arr.Length; write++) {
    for (int sort = 0; sort < arr.Length - 1; sort++) {
        if (arr[sort] > arr[sort + 1]) {
            temp = arr[sort + 1];
            arr[sort + 1] = arr[sort];
            arr[sort] = temp;
        }
    }
}

for (int i = 0; i < arr.Length; i++)
    Console.Write(arr[i] + " ");

Console.ReadKey();

回答by McAden

Your Console.Write("{0} ", arr[write]);is too early. You're printing the values while the sort is still in progress. For example, you're printing 9as being index 3 in the array, yet on the very next iteration of the loop the 9has moved to index 2 and 240has moved to index 3... yet you're outer loop has moved forward so it prints 649the second time and 240never gets printed.

Console.Write("{0} ", arr[write]);的太早了 您在排序仍在进行时打印值。例如,您正在打印9为数组中的索引 3,但在循环的下一次迭代中,它9已移至索引 2 并240已移至索引 3……但您的外循环已向前移动,因此它649第二次打印并且240永远不会打印。

回答by azuneca

This one works for me

这个对我有用

public static int[] SortArray(int[] array)
{
    int length = array.Length;

    int temp = array[0];

    for (int i = 0; i < length; i++)
    {
        for (int j = i+1; j < length; j++)
        {
            if (array[i] > array[j])
            {
                temp = array[i];

                array[i] = array[j];

                array[j] = temp;
            }
        }
    }

    return array;        
}

回答by Dima

I saw someone use this example as part of a job application test. My feedback to him was that it lacks an escape from the outer loop when the array is mostly sorted.

我看到有人使用这个例子作为工作申请测试的一部分。我给他的反馈是,当数组大部分被排序时,它无法摆脱外循环。

consider what would happen in this case:

考虑在这种情况下会发生什么:

int[] arr = {1,2,3,4,5,6,7,8};

here's something that makes more sense:

这是更有意义的事情:

int[] arr = {1,2,3,4,5,6,7,8};

int temp = 0;
int loopCount=0;
bool doBreak=true;

for (int write = 0; write < arr.Length; write++)
{
    doBreak=true;
    for (int sort = 0; sort < arr.Length - 1; sort++)
    {
        if (arr[sort] > arr[sort + 1])
        {
            temp = arr[sort + 1];
            arr[sort + 1] = arr[sort];
            arr[sort] = temp;
            doBreak=false;
        }
        loopCount++;
    }
    if(doBreak){ break; /*early escape*/ }
}

Console.WriteLine(loopCount);
for (int i = 0; i < arr.Length; i++) Console.Write(arr[i] + " ");

回答by Bharat Patil

int[] arr = { 800, 11, 50, 771, 649, 770, 240, 9 };

int temp = 0;

for (int write = 0; write < arr.Length; write++)
{
    for (int sort = 0; sort < arr.Length - 1 - write ; sort++)
    {
        if (arr[sort] > arr[sort + 1])
        {
            temp = arr[sort + 1];
            arr[sort + 1] = arr[sort];
            arr[sort] = temp;
        }
    }
}

for (int i = 0; i < arr.Length; i++) Console.Write(arr[i] + " ");

Console.ReadKey();

回答by Srdjan Rajcevic

int[] array = new int[10] { 13, 2, 5, 8, 23, 90, 41, 4, 77, 61 };

for (int i = 10; i > 0; i--)
{
    for (int j = 0; j < 9; j++)
    {
        if (array[j] > array[j + 1])
        {
            int temp = array[j];
            array[j] = array[j + 1];
            array[j + 1] = temp;
        }
    }
}

回答by edison2001ren

    static bool BubbleSort(ref List<int> myList, int number)
    {
        if (number == 1)
            return true;
        for (int i = 0; i < number; i++)
        {
            if ((i + 1 < number) && (myList[i] > myList[i + 1]))
            {
                int temp = myList[i];
                myList[i] = myList[i + 1];
                myList[i + 1] = temp;
            }
            else
                continue;
        }
        return BubbleSort(ref myList, number - 1);
    }

回答by RolandoCC

Just another example but with an outter WHILE loop instead of a FOR:

只是另一个示例,但使用外部 WHILE 循环而不是 FOR:

public static void Bubble()
    {
        int[] data = { 5, 4, 3, 2, 1 };
        bool newLoopNeeded = false;
        int temp;
        int loop = 0;

        while (!newLoopNeeded)
        {
            newLoopNeeded = true;
            for (int i = 0; i < data.Length - 1; i++)
            {
                if (data[i + 1] < data[i])
                {
                    temp = data[i];
                    data[i] = data[i + 1];
                    data[i + 1] = temp;
                    newLoopNeeded = false;
                }
                loop++;
            }
        }
    }

回答by kiran ganta

int[] arr = { 800, 11, 50, 771, 649, 770, 240, 9 };
for (int i = 0; i < arr.Length; i++)
{
    for (int j = i; j < arr.Length ; j++)
    {
        if (arr[j] < arr[i])
        {
            int temp = arr[i];
            arr[i] = arr[j];
            arr[j] = temp;
        }
    }
}
Console.ReadLine();

回答by Nikoo

public static void BubbleSort(int[] a)
    {

       for (int i = 1; i <= a.Length - 1; ++i)

            for (int j = 0; j < a.Length - i; ++j)

                if (a[j] > a[j + 1])


                    Swap(ref a[j], ref a[j + 1]);

    }

    public static void Swap(ref int x, ref int y)
    {
        int temp = x;
        x = y;
        y = temp;
    }