Java 无法构造 `class name` 的实例(尽管至少在 Creator 上存在)

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时间:2020-08-11 01:10:14  来源:igfitidea点击:

Cannot construct instance of `class name` (although at least on Creator exists)

javajsonspringHymanson

提问by Slippy

I have the following class, which I am using as a request payload :

我有以下类,我将其用作请求有效负载:

public class SampleRequest {

    private String fromDate;
    private String toDate;

    // Getters and setters removed for brevity.
}

I am trying to use it with this resource below (just trying to print it to screen to see things happen) :

我正在尝试将它与下面的这个资源一起使用(只是试图将它打印到屏幕上以查看发生的事情):

@PostMapping("/getBySignatureOne")
public ResponseEntity<?> getRequestInfo(@Valid @RequestBody SampleRequest signatureOneRequest) {

    System.out.println(signatureOneRequest.getToDate);
    System.out.println(signatureOneRequest.getFromDate);
}

This is the JSON request I send up :

这是我发送的 JSON 请求:

{
    "fromDate":"2019-03-09",
    "toDate":"2019-03-10"
}

This is the error I get :

这是我得到的错误:

Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot construct instance of `com.test.app.payload.SampleRequest` (although at least one Creator exists): no String-argument constructor/factory method to deserialize from String value ('fromDate'); nested exception is com.fasterxml.Hymanson.databind.exc.MismatchedInputException: Cannot construct instance of `com.test.app.payload.SampleRequest` (although at least one Creator exists): no String-argument constructor/factory method to deserialize from String value ('fromDate')
 at [Source: (PushbackInputStream); line: 1, column: 2]]

I'd love to know what's wrong here, I suspect its an issue with constructors, or that I am missing some annotation somewhere, but I am honestly unsure of where I have gone wrong.

我很想知道这里出了什么问题,我怀疑这是构造函数的问题,或者我在某处丢失了一些注释,但老实说我不确定我哪里出错了。

采纳答案by Andronicus

You need a constructor with all parameters:

您需要一个带有所有参数的构造函数:

public SampleRequest(String fromDate, String toDate) {

    this.fromDate = fromDate;
    this.toDate = toDate;

}

Or using @AllArgsConstructoror @Datafrom lombok.

或使用@AllArgsConstructor@Data来自龙目岛。

回答by dextermini

Hi you need to write custom deserializer as it not able to parse String (fromDate and toDate) to Date

嗨,您需要编写自定义反序列化器,因为它无法将字符串(fromDate 和 toDate)解析为 Date

{ "fromDate":"2019-03-09", "toDate":"2019-03-10" }

{ "fromDate":"2019-03-09", "toDate":"2019-03-10" }

this link has a tutorial to get started with custom deserializer https://www.baeldung.com/Hymanson-deserialization

此链接有一个教程,可以开始使用自定义反序列化器https://www.baeldung.com/Hymanson-deserialization

Deserializer could be written like this.

解串器可以这样写。

public class CustomDateDeserializer extends StdDeserializer<Date> {

private static SimpleDateFormat formatter = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");

public CustomDateDeserializer() {
    this(null);
}

public CustomDateDeserializer(Class<?> vc) {
    super(vc);
}

@Override
public Date deserialize(JsonParser jsonparser, DeserializationContext context) throws IOException {
    String date = jsonparser.getText();
    try {
        return formatter.parse(date);
    } catch (ParseException e) {
        throw new RuntimeException(e);
    }
}}

You can register the deserializer at Class itself like this.

您可以像这样在 Class 本身注册反序列化器。

@JsonDeserialize(using = ItemDeserializer.class)
public class Item {  ...}

Or either you can register custom deserializer manually like this

或者您可以像这样手动注册自定义解串器

ObjectMapper mapper = new ObjectMapper();
SimpleModule module = new SimpleModule();
module.addDeserializer(Item.class, new ItemDeserializer());
mapper.registerModule(module);