php 如何删除查询字符串并仅获取网址？
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How to remove the querystring and get only the url?
提问by Navi Gamage
Im using PHP to build the URL of the current page. Sometimes, URLs in the form of
我使用 PHP 来构建当前页面的 URL。有时，URL 形式为
www.mydomian.com/myurl.html?unwantedthngs
are requested. I want to remove the ?and everything that follows it (querystring), such that the resulting URL becomes:
被要求。我想删除?和它后面的所有内容（查询字符串），这样生成的 URL 变为：
www.mydomain.com/myurl.html
My current code is this:
我目前的代码是这样的：
<?php
function curPageURL() {
$pageURL = 'http';
if ($_SERVER["HTTPS"] == "on") {
$pageURL .= "s";
}
$pageURL .= "://";
if ($_SERVER["SERVER_PORT"] != "80") {
$pageURL .= $_SERVER["SERVER_NAME"] . ":" .
$_SERVER["SERVER_PORT"] . $_SERVER["REQUEST_URI"];
} else {
$pageURL .= $_SERVER["SERVER_NAME"] . $_SERVER["REQUEST_URI"];
}
return $pageURL;
}
?>
回答by RiaD
You can use strtokto get string before first occurence of ?
您可以使用strtok在第一次出现之前获取字符串?
$url = strtok($_SERVER["REQUEST_URI"], '?');
strtok()represents the most concise technique to directly extract the substring before the ?in the querystring. explode()is less direct because it must produce a potentially two-element array by which the first element must be accessed.
strtok()表示直接提取?查询字符串中 之前的子字符串的最简洁的技术。 explode()不太直接，因为它必须生成一个潜在的二元素数组，必须通过该数组访问第一个元素。
Some other techniques may break when the querystring is missing or potentially mutate other/unintended substrings in the url -- these techniques should be avoided.
当查询字符串丢失或潜在地改变 url 中的其他/意外子字符串时，其他一些技术可能会中断——这些技术应该避免。
一个演示：
$urls = [
'www.example.com/myurl.html?unwantedthngs#hastag',
'www.example.com/myurl.html'
];
foreach ($urls as $url) {
var_export(['strtok: ', strtok($url, '?')]);
echo "\n";
var_export(['strstr/true: ', strstr($url, '?', true)]); // not reliable
echo "\n";
var_export(['explode/2: ', explode('?', $url, 2)[0]]); // limit allows func to stop searching after first encounter
echo "\n";
var_export(['substr/strrpos: ', substr($url, 0, strrpos( $url, "?"))]); // not reliable; still not with strpos()
echo "\n---\n";
}
Output:
输出：
array (
0 => 'strtok: ',
1 => 'www.example.com/myurl.html',
)
array (
0 => 'strstr/true: ',
1 => 'www.example.com/myurl.html',
)
array (
0 => 'explode/2: ',
1 => 'www.example.com/myurl.html',
)
array (
0 => 'substr/strrpos: ',
1 => 'www.example.com/myurl.html',
)
---
array (
0 => 'strtok: ',
1 => 'www.example.com/myurl.html',
)
array (
0 => 'strstr/true: ',
1 => false, // bad news
)
array (
0 => 'explode/2: ',
1 => 'www.example.com/myurl.html',
)
array (
0 => 'substr/strrpos: ',
1 => '', // bad news
)
---
回答by veritas
Use PHP Manual - parse_url()to get the parts you need.
使用PHP 手册 - parse_url()获取您需要的部分。
Edit (example usage for @Navi Gamage)
编辑（@Navi Gamage 的示例用法）
You can use it like this:
你可以这样使用它：
<?php
function reconstruct_url($url){
$url_parts = parse_url($url);
$constructed_url = $url_parts['scheme'] . '://' . $url_parts['host'] . $url_parts['path'];
return $constructed_url;
}
?>
Edit (second full example):
编辑（第二个完整示例）：
Updated function to make sure scheme will be attached and none notice msgs appear:
更新功能以确保将附加方案并且不会出现任何通知消息：
function reconstruct_url($url){
$url_parts = parse_url($url);
$constructed_url = $url_parts['scheme'] . '://' . $url_parts['host'] . (isset($url_parts['path'])?$url_parts['path']:'');
return $constructed_url;
}
$test = array(
'http://www.mydomian.com/myurl.html?unwan=abc',
'http://www.mydomian.com/myurl.html',
'http://www.mydomian.com',
'https://mydomian.com/myurl.html?unwan=abc&ab=1'
);
foreach($test as $url){
print_r(parse_url($url));
}
Will return:
将返回：
Array
(
[scheme] => http
[host] => www.mydomian.com
[path] => /myurl.html
[query] => unwan=abc
)
Array
(
[scheme] => http
[host] => www.mydomian.com
[path] => /myurl.html
)
Array
(
[scheme] => http
[host] => www.mydomian.com
)
Array
(
[path] => mydomian.com/myurl.html
[query] => unwan=abc&ab=1
)
This is the output from passing example urls through parse_url() with no second parameter (for explanation only).
这是通过 parse_url() 传递示例 url 的输出，没有第二个参数（仅用于解释）。
And this is the final output after constructing url using:
这是使用以下方法构建 url 后的最终输出：
foreach($test as $url){
echo reconstruct_url($url) . '<br/>';
}
Output:
输出：
http://www.mydomian.com/myurl.html
http://www.mydomian.com/myurl.html
http://www.mydomian.com
https://mydomian.com/myurl.html
回答by Ludo - Off the record
best solution:
最佳解决方案：
echo parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
No need to include your http://domain.comin your if you're submitting a form to the same domain.
如果您要向同一域提交表单，则无需在您的http://domain.com中包含。
回答by zellio
$val = substr( $url, 0, strrpos( $url, "?"));
回答by Mukesh Saxena
Most Easiest Way
最简单的方法
$url = 'https://www.youtube.com/embed/ROipDjNYK4k?rel=0&autoplay=1';
$url_arr = parse_url($url);
$query = $url_arr['query'];
print $url = str_replace(array($query,'?'), '', $url);
//output
https://www.youtube.com/embed/ROipDjNYK4k
回答by James Bordine II
You'll need at least PHP Version 5.4 to implement this solution without exploding into a variable on one line and concatenating on the next, but an easy one liner would be:
您至少需要 PHP 5.4 版才能实现此解决方案，而不会在一行上分解为变量并在下一行连接，但一个简单的一行代码是：
$_SERVER["HTTP_HOST"].explode('?', $_SERVER["REQUEST_URI"], 2)[0];
Server Variables: http://php.net/manual/en/reserved.variables.server.php
Array Dereferencing: https://wiki.php.net/rfc/functionarraydereferencing
服务器变量：http: //php.net/manual/en/reserved.variables.server.php
数组解引用：https: //wiki.php.net/rfc/functionarraydereferencing
回答by Mohammad altenji
You can use the parse_url build in function like that:
您可以像这样使用 parse_url 内置函数：
$baseUrl = $_SERVER['SERVER_NAME'] . parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
回答by ysrb
You can try:
你可以试试：
<?php
$this_page = basename($_SERVER['REQUEST_URI']);
if (strpos($this_page, "?") !== false) $this_page = reset(explode("?", $this_page));
?>
回答by user1079877
If you want to get request path (more info):
如果您想获取请求路径（更多信息）：
echo parse_url($_SERVER["REQUEST_URI"])['path']
If you want to remove the query and (and maybe fragment also):
如果您想删除查询和（也可能是片段）：
function strposa($haystack, $needles=array(), $offset=0) {
$chr = array();
foreach($needles as $needle) {
$res = strpos($haystack, $needle, $offset);
if ($res !== false) $chr[$needle] = $res;
}
if(empty($chr)) return false;
return min($chr);
}
$i = strposa($_SERVER["REQUEST_URI"], ['#', '?']);
echo strrpos($_SERVER["REQUEST_URI"], 0, $i);
回答by Ryan Prechel
To remove the query string from the request URI, replace the query string with an empty string:
要从请求 URI 中删除查询字符串，请将查询字符串替换为空字符串：
function request_uri_without_query() {
$result = $_SERVER['REQUEST_URI'];
$query = $_SERVER['QUERY_STRING'];
if(!empty($query)) {
$result = str_replace('?' . $query, '', $result);
}
return $result;
}
