Jquery - 将 Ajax JSON 响应存储为变量
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/4763918/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Jquery - Store Ajax jSON response as variable
提问by Sebastien
I'm trying to get the result of an ajax request to set in a variable which I can access outside that request. I've tried this JQuery - Storing ajax response into global variablebut my variable beerremains undefined outside the $.getJSONand $.ajaxfunctions (I tried both).
我试图将 ajax 请求的结果设置在一个我可以在该请求之外访问的变量中。我试过这个JQuery - 将 ajax 响应存储到全局变量中，但我的变量beer在$.getJSON和$.ajax函数之外仍未定义（我都试过）。
Here is my code and where I am able to see the results from the console.log(beer).
这是我的代码，我可以在这里看到console.log(beer).
var beer;
$.getJSON(jsonUrl, function (json) {
beer = json;
console.log(beer); // returns beer
});
console.log(beer); // returns undefined
var beer = (function () {
var result;
$.ajax({
url: jsonUrl,
success: function (data) {
result = data;
console.log(beer); // returns beer
}
});
console.log(result); // returns undefined
if (result) return result;
})();
console.log(beer); // returns undefined
回答by chprpipr
That's an asynchronous request, so it gets fired off, but your script doesn't wait around for a response before it moves on. If you need to wait on a ajax request to finish, try something like this:
这是一个异步请求，因此它会被触发，但是您的脚本在继续之前不会等待响应。如果您需要等待 ajax 请求完成，请尝试以下操作：
var beer;
$.getJSON(jsonUrl,function(json){
beer = json;
checkDrink();
});
function checkDrink() {
console.log(beer);
}
回答by userlond
Suggest the code below:
建议使用以下代码：
var beer = $.ajax({
url: jsonUrl,
async: false,
dataType: 'json'
}).responseJSON;
The key moments are:
关键时刻是：
- set
asyncto false, to return result as variable, not call success callback asynchronious - set
dataTypeto json to parse server response string as json
- 设置
async为false，将结果作为变量返回，而不是异步调用成功回调 - 设置
dataType为 json 以将服务器响应字符串解析为 json
回答by Jaime
The problem is that you're trying to access the data before it actually comes back from the server, the 'success' function is actually a callback that gets called when the ajax call finishes successfully. The $.ajax (or $.get) functions return inmediatly...
问题是您试图在数据实际从服务器返回之前访问数据，“成功”函数实际上是一个回调，当 ajax 调用成功完成时会调用它。$.ajax（或 $.get）函数立即返回......
You would need to somehow signal to the interested functions that you got the data into the 'beer' var inside your success callback
您需要以某种方式向感兴趣的函数发出信号，表明您已将数据放入成功回调中的“啤酒”变量中
