将 Jackson 对象转换为 JSONObject java
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Convert Hymanson object into JSONObject java
提问by Code Junkie
I'm trying to figure out how to convert a Hymanson object into a JSONObject?
我想弄清楚如何将 Hymanson 对象转换为 JSONObject？
What I've tried, however I don't believe this is the correct approach.
我已经尝试过，但是我不相信这是正确的方法。
public JSONObject toJSON() throws IOException {
ObjectMapper mapper = new ObjectMapper();
return new JSONObject(mapper.writeValueAsString(new Warnings(warnings)));
}
回答by Sotirios Delimanolis
Right now, you are serializing your Pojo to a String, then parsing that Stringand converting it into a HashMapstyle object in the form of JSONObject.
现在，您正在将 Pojo 序列化为String，然后对其进行解析String并将其转换HashMap为JSONObject.
This is very inefficient and doesn't accomplish anything of benefit.
这是非常低效的，并没有完成任何有益的事情。
Hymanson already provides an ObjectNodeclass for interacting with your Pojo as a JSON object. So just convert your object to an ObjectNode. Here's a working example
Hymanson 已经提供了一个ObjectNode类，用于作为 JSON 对象与您的 Pojo 交互。所以只需将您的对象转换为ObjectNode. 这是一个工作示例
public class Example {
public static void main(String[] args) throws Exception {
Pojo pojo = new Pojo();
pojo.setAge(42);
pojo.setName("Sotirios");
ObjectMapper mapper = new ObjectMapper();
ObjectNode node = mapper.valueToTree(pojo);
System.out.println(node);
}
}
class Pojo {
private String name;
private int age;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
}
Otherwise, the way you are doing it is fine.
否则，你这样做的方式很好。
回答by MacDaddy
The way you are doing is work fine, because i also use that way to make a JSONobject.
你这样做的方式很好，因为我也用这种方式来制作一个 JSONobject。
here is my code
这是我的代码
public JSONObject getRequestJson(AccountInquiryRequestVO accountInquiryRequestVO) throws JsonGenerationException, JsonMappingException, IOException {
ObjectMapper mapper = new ObjectMapper();
JSONObject jsonAccountInquiry;
jsonAccountInquiry=new JSONObject(mapper.writeValueAsString(accountInquiryRequestVO));
return jsonAccountInquiry;
}
its working fine for me. but you can always use JsonNode also here is the sample code for that
它对我来说工作正常。但你总是可以使用 JsonNode 也是这里的示例代码
JsonNode jsonNode=mapper.valueToTree(accountInquiryRequestVO);
its very easy to use.
它非常容易使用。
