JavaScript - 比较两个多维数组
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/16437307/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
JavaScript - Compare two multidimensional arrays
提问by mihajlo
I have two multidimensional arrays:
我有两个多维数组：
first is something like (['one','one','three'],['four','five',five'],['one','one','one'])
首先是类似的东西 (['one','one','three'],['four','five',five'],['one','one','one'])
and the second one is like this (['one','one','nine'],['one','one','one'],['two','two'],['two','two','two']...)
第二个是这样的 (['one','one','nine'],['one','one','one'],['two','two'],['two','two','two']...)
Now, what I want is to find match first index of first array with second array, but position of at least first two indexes from boths array must match also, eg.:
现在，我想要的是找到第一个数组的第一个索引与第二个数组的匹配，但是两个数组中至少前两个索引的位置也必须匹配，例如：
first_array (['one','one','three'],['four','five',five'],['one','one','one'])
first_array ( ['one','one','three'],['four','five',five'],['one','one','one'])
will match
会匹配
second_array (['one','one','nine'],['one','one','one'],['two','two']['two','two','two']...)
second_array ( ['one','one','nine'],['one','one','one'],['two','two']['two','two','two ']...）
and output would be eg. 'alert('Match.').
和输出将是例如。'警报（'匹配。'）。
I have tried
我努力了
for(i=0; i<1; i++){
if(first_array[0] == second_array) console.log('Match');
else console.log('No match');
}
but I constantly get 'No match' although there is a match. P.S. in 'for' loop, my i is i<1 because I want to compare only first index of first_array with complete second_array.
但我经常得到“不匹配”，尽管有匹配。PS在'for'循环中，我的i是i<1，因为我只想将first_array的第一个索引与完整的second_array进行比较。
Thanks in advance
提前致谢
回答by Kevin Bowersox
var md1 = [['one','one','three'],['four','five','five'],['one','one','one']];
var md2 = [['one','one','nine'],['one','one','one'],['two','two'],['two','two','two']];
//Iterate through all elements in first array
for(var x = 0; x < md1.length; x++){
//Iterate through all elements in second array
for(var y = 0; y < md2.length; y++){
/*This causes us to compare all elements
in first array to each element in second array
Since md1[x] stays fixed while md2[y] iterates through second array.
We compare the first two indexes of each array in conditional
*/
if(md1[x][0] == md2[y][0] && md1[x][1] == md2[y][1]){
alert("match found");
alert("Array 1 element with index " + x + " matches Array 2 element with index " + y);
}
}
}
Working Examplehttp://jsfiddle.net/2nxBb/1/
回答by Robbert
Possible duplicate of How to compare arrays in JavaScript?.
可能的重复如何在JavaScript中比较数组？.
For a strict array comparison, check their length and values like so:
对于严格的数组比较，请检查它们的长度和值，如下所示：
var a1 = [1, 2, 3];
var a2 = [1, 2, 3];
array_compare(a1, a2);
function array_compare(a1, a2) {
if(a1.length != a2.length) {
return false;
}
for(var i in a1) {
// Don't forget to check for arrays in our arrays.
if(a1[i] instanceof Array && a2[i] instanceof Array) {
if(!array_compare(a1[i], a2[i])) {
return false;
}
}
else if(a1[i] != a2[i]) {
return false;
}
}
return true;
}
