Java HtmlUnit 按钮单击
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HtmlUnit button click
提问by altoids
I'm trying to send a message on www.meetme.com but can't figure out how to do it. I can type in the message in the comment area but clicking the Send button doesn't do anything. What am I doing wrong? When I login and press the Login button the page does change and everything is fine. Anyone have any ideas or clues?
我正在尝试在 www.meetme.com 上发送消息，但不知道该怎么做。我可以在评论区输入消息，但点击发送按钮没有任何作用。我究竟做错了什么？当我登录并按登录按钮时，页面确实发生了变化，一切都很好。任何人有任何想法或线索？
HtmlPage htmlPage = null;
HtmlElement htmlElement;
WebClient webClient = null;
HtmlButton htmlButton;
HtmlForm htmlForm;
try{
// Create and initialize WebClient object
webClient = new WebClient(BrowserVersion.FIREFOX_17 );
webClient.setCssEnabled(false);
webClient.setJavaScriptEnabled(false);
webClient.setThrowExceptionOnFailingStatusCode(false);
webClient.setThrowExceptionOnScriptError(false);
webClient.getOptions().setThrowExceptionOnScriptError(false);
webClient.getOptions().setUseInsecureSSL(true);
webClient.getCookieManager().setCookiesEnabled(true);
/*webClient.setRefreshHandler(new RefreshHandler() {
public void handleRefresh(Page page, URL url, int arg) throws IOException {
System.out.println("handleRefresh");
}
});*/
htmlPage = webClient.getPage("http://www.meetme.com");
htmlForm = htmlPage.getFirstByXPath("//form[@action='https://ssl.meetme.com/login']");
htmlForm.getInputByName("username").setValueAttribute("[email protected]");
htmlForm.getInputByName("password").setValueAttribute("blah");
//Signing in
htmlButton = htmlForm.getElementById("login_form_submit");
htmlPage = (HtmlPage) htmlButton.click();
htmlPage = webClient.getPage("http://www.meetme.com/member/1234567890");
System.out.println("BEFORE CLICK");
System.out.println(htmlPage.asText());
//type message in text area
HtmlTextArea commentArea = (HtmlTextArea)htmlPage.getFirstByXPath("//textarea[@id='profileQMBody']");
commentArea.setText("Testing");
htmlButton = (HtmlButton) htmlPage.getHtmlElementById("profileQMSend");
htmlPage = (HtmlPage)htmlButton.click();
webClient.waitForBackgroundJavaScript(7000);
//The print is exactly the same as the BEFORE CLICK print
System.out.println("AFTER CLICK");
System.out.println(htmlPage.asText());
}catch(ElementNotFoundException e){
e.printStackTrace();
}catch(Exception e){
e.printStackTrace();
}
采纳答案by Mosty Mostacho
Without knowing much about the webpage you're accessing, you just can't perform an AJAX request with JavaScript disabled. If changing that doesn't result in success, then you will have to keep debugging, but make sure JavaScript is enabled.
如果不了解您正在访问的网页，您就无法在禁用 JavaScript 的情况下执行 AJAX 请求。如果更改没有成功，那么您将不得不继续调试，但要确保启用了 JavaScript。
Additionally, make sure you're using HtmlUnit 1.12 and update all the deprecated methods in your code.
此外，请确保您使用的是 HtmlUnit 1.12 并更新代码中所有已弃用的方法。
BTW, I'd also recommend to turn may JavaScript warnings off. Check this answerto see how you can do that.
顺便说一句，我还建议关闭可能的 JavaScript 警告。检查此答案以了解如何执行此操作。
