在 PHP 中格式化电话号码
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Formatting Phone Numbers in PHP
提问by NightMICU
I am working on an SMS appand need to be able to convert the sender's phone number from +11234567890to 123-456-7890so it can be compared to records in a MySQL database.
我正在开发一个SMS 应用程序，需要能够将发件人的电话号码从+11234567890 转换为123-456-7890，以便可以将其与MySQL 数据库中的记录进行比较。
The numbers are stored in the latter format for use elsewhere on the site and I would rather not change that format as it would require modifying a lot of code.
这些数字以后一种格式存储，以便在网站的其他地方使用，我宁愿不更改该格式，因为它需要修改大量代码。
How would I go about this with PHP?
我将如何用 PHP 解决这个问题？
Thanks!
谢谢！
回答by Xeoncross
This is a US phone formatter that works on more versions of numbers than any of the current answers.
这是一种美国电话格式化程序，可以处理比任何当前答案都多的数字版本。
$numbers = explode("\n", '(111) 222-3333
((111) 222-3333
1112223333
111 222-3333
111-222-3333
(111)2223333
+11234567890
1-8002353551
123-456-7890 -Hello!
+1 - 1234567890
');
foreach($numbers as $number)
{
print preg_replace('~.*(\d{3})[^\d]{0,7}(\d{3})[^\d]{0,7}(\d{4}).*~', '() -', $number). "\n";
}
And here is a breakdown of the regex:
这是正则表达式的细分：
Cell: +1 999-(555 0001)
.* zero or more of anything "Cell: +1 "
(\d{3}) three digits "999"
[^\d]{0,7} zero or up to 7 of something not a digit "-("
(\d{3}) three digits "555"
[^\d]{0,7} zero or up to 7 of something not a digit " "
(\d{4}) four digits "0001"
.* zero or more of anything ")"
Updated: March 11, 2015 to use {0,7}instead of {,7}
更新时间：2015 年 3 月 11 日以{0,7}代替使用{,7}
回答by slier
$data = '+11234567890';
if( preg_match( '/^\+\d(\d{3})(\d{3})(\d{4})$/', $data, $matches ) )
{
$result = $matches[1] . '-' .$matches[2] . '-' . $matches[3];
return $result;
}
回答by Bryan Schoen
This function will format international (10+ digit), non-international (10 digit) or old school (7 digit) phone numbers. Any numbers other than 10+, 10 or 7 digits will remain unformatted.
此功能将格式化国际（10 位以上）、非国际（10 位）或老式（7 位）电话号码。除 10+、10 或 7 位数字以外的任何数字将保持未格式化。
function formatPhoneNumber($phoneNumber) {
$phoneNumber = preg_replace('/[^0-9]/','',$phoneNumber);
if(strlen($phoneNumber) > 10) {
$countryCode = substr($phoneNumber, 0, strlen($phoneNumber)-10);
$areaCode = substr($phoneNumber, -10, 3);
$nextThree = substr($phoneNumber, -7, 3);
$lastFour = substr($phoneNumber, -4, 4);
$phoneNumber = '+'.$countryCode.' ('.$areaCode.') '.$nextThree.'-'.$lastFour;
}
else if(strlen($phoneNumber) == 10) {
$areaCode = substr($phoneNumber, 0, 3);
$nextThree = substr($phoneNumber, 3, 3);
$lastFour = substr($phoneNumber, 6, 4);
$phoneNumber = '('.$areaCode.') '.$nextThree.'-'.$lastFour;
}
else if(strlen($phoneNumber) == 7) {
$nextThree = substr($phoneNumber, 0, 3);
$lastFour = substr($phoneNumber, 3, 4);
$phoneNumber = $nextThree.'-'.$lastFour;
}
return $phoneNumber;
}
回答by Daniel Hepper
Assuming that your phone numbers always have this exact format, you can use this snippet:
假设您的电话号码始终采用这种精确格式，您可以使用以下代码段：
$from = "+11234567890";
$to = sprintf("%s-%s-%s",
substr($from, 2, 3),
substr($from, 5, 3),
substr($from, 8));
回答by likeitlikeit
Phone numbers are hard. For a more robust, international solution, I would recommend this well-maintained PHP portof Google's libphonenumberlibrary.
电话号码很难。对于更强大、更国际化的解决方案，我会推荐Google 的libphonenumber库的这个维护良好的 PHP 端口。
Using it like this,
像这样使用它，
use libphonenumber\NumberParseException;
use libphonenumber\PhoneNumber;
use libphonenumber\PhoneNumberFormat;
use libphonenumber\PhoneNumberUtil;
$phoneUtil = PhoneNumberUtil::getInstance();
$numberString = "+12123456789";
try {
$numberPrototype = $phoneUtil->parse($numberString, "US");
echo "Input: " . $numberString . "\n";
echo "isValid: " . ($phoneUtil->isValidNumber($numberPrototype) ? "true" : "false") . "\n";
echo "E164: " . $phoneUtil->format($numberPrototype, PhoneNumberFormat::E164) . "\n";
echo "National: " . $phoneUtil->format($numberPrototype, PhoneNumberFormat::NATIONAL) . "\n";
echo "International: " . $phoneUtil->format($numberPrototype, PhoneNumberFormat::INTERNATIONAL) . "\n";
} catch (NumberParseException $e) {
// handle any errors
}
you will get the following output:
您将获得以下输出：
Input: +12123456789
isValid: true
E164: +12123456789
National: (212) 345-6789
International: +1 212-345-6789
I'd recommend using the E164format for duplicate checks. You could also check whether the number is a actually mobile number or not (using PhoneNumberUtil::getNumberType()), or whether it's even a US number (using PhoneNumberUtil::getRegionCodeForNumber()).
我建议使用E164重复检查的格式。您还可以检查该号码是否是实际的手机号码（使用PhoneNumberUtil::getNumberType()），或者甚至是美国号码（使用PhoneNumberUtil::getRegionCodeForNumber()）。
As a bonus, the library can handle pretty much any input. If you, for instance, choose to run 1-800-JETBLUEthrough the code above, you will get
作为奖励，该库几乎可以处理任何输入。例如，如果您选择运行1-800-JETBLUE上面的代码，您将获得
Input: 1-800-JETBLUE
isValid: true
E164: +18005382583
National: (800) 538-2583
International: +1 800-538-2583
Neato.
尼托。
It works just as nicely for countries other than the US. Just use another ISO country code in the parse()argument.
它对美国以外的国家也同样有效。只需在parse()参数中使用另一个 ISO 国家/地区代码即可。
回答by skibulk
Here's my USA-only solution, with the area code as an optional component, required delimiter for the extension, and regex comments:
这是我的仅限美国的解决方案，区号作为可选组件，扩展所需的分隔符和正则表达式注释：
function formatPhoneNumber($s) {
$rx = "/
(1)?\D* # optional country code
(\d{3})?\D* # optional area code
(\d{3})\D* # first three
(\d{4}) # last four
(?:\D+|$) # extension delimiter or EOL
(\d*) # optional extension
/x";
preg_match($rx, $s, $matches);
if(!isset($matches[0])) return false;
$country = $matches[1];
$area = $matches[2];
$three = $matches[3];
$four = $matches[4];
$ext = $matches[5];
$out = "$three-$four";
if(!empty($area)) $out = "$area-$out";
if(!empty($country)) $out = "+$country-$out";
if(!empty($ext)) $out .= "x$ext";
// check that no digits were truncated
// if (preg_replace('/\D/', '', $s) != preg_replace('/\D/', '', $out)) return false;
return $out;
}
And here's the script to test it:
这是测试它的脚本：
$numbers = [
'3334444',
'2223334444',
'12223334444',
'12223334444x5555',
'333-4444',
'(222)333-4444',
'+1 222-333-4444',
'1-222-333-4444ext555',
'cell: (222) 333-4444',
'(222) 333-4444 (cell)',
];
foreach($numbers as $number) {
print(formatPhoneNumber($number)."<br>\r\n");
}
回答by Zeromatik
Here's a simple function for formatting phone numbers with 7 to 10 digits in a more European (or Swedish?) manner:
这是一个简单的函数，用于以更欧洲（或瑞典？）的方式格式化 7 到 10 位数字的电话号码：
function formatPhone($num) {
$num = preg_replace('/[^0-9]/', '', $num);
$len = strlen($num);
if($len == 7) $num = preg_replace('/([0-9]{2})([0-9]{2})([0-9]{3})/', ' ', $num);
elseif($len == 8) $num = preg_replace('/([0-9]{3})([0-9]{2})([0-9]{3})/', ' - ', $num);
elseif($len == 9) $num = preg_replace('/([0-9]{3})([0-9]{2})([0-9]{2})([0-9]{2})/', ' - ', $num);
elseif($len == 10) $num = preg_replace('/([0-9]{3})([0-9]{2})([0-9]{2})([0-9]{3})/', ' - ', $num);
return $num;
}
回答by Viktor Jarnheimer
Don't reinvent the wheel! Import this amazing library:
https://github.com/giggsey/libphonenumber-for-php
不要重新发明轮子！导入这个惊人的库：https:
//github.com/giggsey/libphonenumber-for-php
$defaultCountry = 'SE'; // Based on the country of the user
$phoneUtil = PhoneNumberUtil::getInstance();
$swissNumberProto = $phoneUtil->parse($phoneNumber, $defaultCountry);
return $phoneUtil->format($swissNumberProto, PhoneNumberFormat::INTERNATIONAL);
It is based on Google's library for parsing, formatting, and validating international phone numbers: https://github.com/google/libphonenumber
它基于 Google 的用于解析、格式化和验证国际电话号码的库：https: //github.com/google/libphonenumber
回答by Ali Lown
I see this being possible using either some regex, or a few substr calls (assuming the input is always of that format, and doesn't change length etc.)
我认为这可以使用一些正则表达式或一些 substr 调用（假设输入始终是那种格式，并且不会改变长度等）
something like
就像是
$in = "+11234567890"; $output = substr($in,2,3)."-".substr($in,6,3)."-".substr($in,10,4);
should do it.
应该这样做。
回答by RobertPitt
Try something like:
尝试类似：
preg_replace('/\d{3}/', '##代码##-', str_replace('.', null, trim($number)), 2);
this would take a $number of 8881112222and convert to 888-111-2222. Hope this helps.
这将需要一个 $number8881112222并转换为888-111-2222. 希望这可以帮助。
