java For 循环乘数

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时间:2020-11-03 01:33:18  来源:igfitidea点击:

For Loop Multiplying Number

java

提问by hama

I need some help -

我需要一些帮助 -

At the end of a for loop, I need to set an original value to the next multiple of the value.

在 for 循环结束时,我需要将原始值设置为该值的下一个倍数。

This is what I have so far -

这是我到目前为止 -

int originalNumber = 1;
for (int i = 1; i <= 10000; i++) { 
  originalNumber *= i;
 }

However, this code will not find the multiples of 1; as the multiples of 1 should be (1, 2, 3, 4, 5, 6, ... ...)

但是,这段代码不会找到 1 的倍数;因为 1 的倍数应该是 (1, 2, 3, 4, 5, 6, ... ...)

This code that I have written will be (1, 1, 2, 6, 24) etc;

我编写的这段代码将是 (1, 1, 2, 6, 24) 等;

What is a good way to get the multiples (inside of the loop)?

获得倍数(在循环内)的好方法是什么?

回答by Jon Skeet

You don't need to change originalNumberat all - just multiply iby originalNumber:

你不需要改变originalNumber在所有-只是乘ioriginalNumber

int originalNumber = 1;
for (int i = 1; i <= 10000; i++) {
    int multiple = originalNumber * i;
    // Use multiple however you want to
}

To get all the multiples of 2, you'd set originalNumberto 2, etc.

要获得 2 的所有倍数,您需要设置originalNumber为 2,依此类推。

回答by Roman ?omowski

You ask for version without additional variable:

您要求没有附加变量的版本:

int originalNumber = 1;
for (int multiple = originalNumber; multiple <= 10000; multiple += originalNumber) {
    // Use multiple however you want to
}

回答by Sean

 int n = scanner.nextInt();
       for (int i = 1; i <= 10;  i++){
         int multiple = i * n;
         System.out.println(n + " x " + i + " = " + multiple);
        } 

You can try this code, it prints any multiple till 10; Your Output (stdout) 2 x 1 = 2
2 x 2 = 4 ... 2 x 10 = 20

你可以试试这个代码,它打印到 10 的任意倍数;你的输出 (stdout) 2 x 1 = 2
2 x 2 = 4 ... 2 x 10 = 20