C++ 或 C 中的 foo(void) 和 foo() 之间有区别吗？
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Is there a difference between foo(void) and foo() in C++ or C?
提问by Landon
Consider these two function definitions:
考虑这两个函数定义：
void foo() { }
void foo(void) { }
Is there any difference between these two? If not, why is the voidargument there? Aesthetic reasons?
这两者有什么区别吗？如果没有，为什么会有void争论？审美原因？
回答by DrPizza
In C:
在C 中：
void foo()means "a functionfootaking an unspecified number of arguments of unspecified type"void foo(void)means "a functionfootaking no arguments"
void foo()表示“foo采用未指定数量的未指定类型参数的函数”void foo(void)意思是“一个foo不带参数的函数”
In C++:
在C++ 中：
void foo()means "a functionfootaking no arguments"void foo(void)means "a functionfootaking no arguments"
void foo()意思是“一个foo不带参数的函数”void foo(void)意思是“一个foo不带参数的函数”
By writing foo(void), therefore, we achieve the same interpretation across both languages and make our headers multilingual (though we usually need to do some more things to the headers to make them truly cross-language; namely, wrap them in an extern "C"if we're compiling C++).
foo(void)因此，通过编写，我们实现了跨两种语言的相同解释并使我们的头文件多语言（尽管我们通常需要对头文件做更多的事情以使其真正跨语言；即，extern "C"如果我们正在编译，将它们包装在一个C++）。
回答by Kyle Cronin
I realize your question pertains to C++, but when it comes to C the answer can be found in K&R, pages 72-73:
我知道您的问题与 C++ 有关，但是当涉及到 C 时，答案可以在 K&R，第 72-73 页中找到：
Furthermore, if a function declaration does not include arguments, as in
double atof();that too is taken to mean that nothing is to be assumed about the arguments of atof; all parameter checking is turned off. This special meaning of the empty argument list is intended to permit older C programs to compile with new compilers. But it's a bad idea to use it with new programs. If the function takes arguments, declare them; if it takes no arguments, use void.
此外，如果函数声明不包含参数，如
double atof();这也意味着对 atof 的参数没有任何假设；关闭所有参数检查。空参数列表的这种特殊含义旨在允许旧的 C 程序使用新的编译器进行编译。但是将它与新程序一起使用是个坏主意。如果函数接受参数，则声明它们；如果不需要参数，则使用 void。
回答by Paul Tomblin
In C, you use a void in an empty function reference so that the compiler has a prototype, and that prototype has "no arguments". In C++, you don't have to tell the compiler that you have a prototype because you can't leave out the prototype.
在 C 中，您在空函数引用中使用 void 以便编译器具有原型，并且该原型“没有参数”。在 C++ 中，您不必告诉编译器您有原型，因为您不能遗漏原型。
