java Spring 测试服务类模拟实用程序类- Junit 和 Mockito
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Spring test service class mocking utility class- Junit and Mockito
提问by Bhabani Sankar Sahoo
I want to write test cases for service layer of spring framework using Junit + Mockito.
我想使用 spring 框架的服务层编写测试用例 Junit + Mockito.
How to call the actual service layer method using my ServiceTest
class, If i mock the ServiceTest
class then it's object wont execute the actual service method code because it wont get the object to call it's methods and if I try with the Spy still it was not working, I tried this examplestill I not able to execute the test cases.
如何使用我的ServiceTest
类调用实际的服务层方法,如果我模拟ServiceTest
该类,那么它的对象不会执行实际的服务方法代码,因为它不会让对象调用它的方法,如果我尝试使用 Spy 仍然无法正常工作,我试过这个例子仍然无法执行测试用例。
MyService.java
我的服务
@Service
public class MyService{
@Autowired
Utility utility;
public String showResult(){
String result = utility.getName();
return result;
}
}
MyServiceTest.java
我的服务测试.java
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(loader=AnnotationConfigWebContextLoader.class)
@WebAppConfiguration
public class MyServiceTest {
@Autowired
MyService myService;
@Autowired
Utility utility;
@Test
public void testShowResult() throws Exception {
assertEquals("Test",myService.showResult());
}
@Configuration
static class MykServiceTestContextConfiguration {
@Bean
public MyService myService() {
return new MyService();
}
@Bean
public Utility utility() {
return Mockito.mock(Utility.class);
}
}
}
回答by Arpit Aggarwal
You have to first mock the Utility
class and then have to invoke it before calling your @Test
using MockitoAnnotations.initMocks(this)
as follows:
您必须首先模拟Utility
该类,然后在调用@Test
using 之前调用它MockitoAnnotations.initMocks(this)
,如下所示:
MyServiceTest.java
我的服务测试.java
import static org.mockito.Mockito.when;
import org.junit.Assert;
import org.junit.Before;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.mockito.InjectMocks;
import org.mockito.Mock;
import org.mockito.MockitoAnnotations;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import org.springframework.test.context.web.AnnotationConfigWebContextLoader;
import org.springframework.test.context.web.WebAppConfiguration;
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(loader = AnnotationConfigWebContextLoader.class)
@WebAppConfiguration
public class MyServiceTest {
@InjectMocks
private MyService myService;
@Mock
private Utility utility;
@Before
public void setupMock() {
MockitoAnnotations.initMocks(this);
}
@Test
public void testShowResult() throws Exception {
when(utility.getName()).thenReturn("Test");
Assert.assertEquals("Test", myService.showResult());
}
@Configuration
static class MykServiceTestContextConfiguration {
@Bean
public MyService myService() {
return new MyService();
}
@Bean
public Utility utility() {
return new Utility();
}
}
}
MyService.java
我的服务
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
@Service
public class MyService {
@Autowired
private Utility utility;
public String showResult() {
String result = utility.getName();
return result;
}
}
Utility.java
实用程序.java
import org.springframework.stereotype.Component;
@Component
public class Utility {
public String getName() {
return "hello";
}
}
回答by hiroyukik
How about using @MockBean
? It suits Spring + JUnit and, probably you need to implement mock behavior.
怎么用@MockBean
?它适合 Spring + JUnit,并且可能您需要实现模拟行为。
I guess that Utility.getName()
return "Test" in the test case.
我想Utility.getName()
在测试用例中返回“Test”。
The following is the test code I tried.
以下是我试过的测试代码。
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(loader = AnnotationConfigWebContextLoader.class)
@WebAppConfiguration
public class MyServiceTest {
@Autowired
MyService myService;
@MockBean
Utility utility;
@Test
public void testShowResult() throws Exception {
Mockito.when(utility.getName()).thenReturn("Test");
assertEquals("Test", myService.showResult());
}
@Configuration
static class MykServiceTestContextConfiguration {
@Bean
public MyService myService() {
return new MyService();
}
}
}
回答by Barath
Make use of @Spy
使用@Spy
When spy is called, then actual method of real object is called.
当 spy 被调用时,则调用真实对象的实际方法。
https://www.tutorialspoint.com/mockito/mockito_spying.htm
https://www.tutorialspoint.com/mockito/mockito_spying.htm
please go through the tutorial
请阅读教程
This worked for me
这对我有用
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration
@WebAppConfiguration
public class MyServiceTest {
@Spy
MyService myService;
@Test
public void testShowResult() throws Exception {
assertEquals("Test",myService.showResult());
}
@Service
public class MyService{
public String showResult(){
return "Test";
}
}
}
still having issues share the spring version you are using
仍然有问题分享您正在使用的 spring 版本