bash ls; 输出修改文件的时间，包括年和秒
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bash ls; output a time of modification of files including year and seconds
提问by Andrey Baulin
I want to output a time of modification of files including year and seconds. I tried to use ls -linT, means -T must do it, but it doesn't. -T is recognized as tabulation size. I'm searching a solution using ls. Could someone help me, please?
我想输出包括年和秒在内的文件修改时间。我尝试使用 ls -linT，意味着 -T 必须这样做，但事实并非如此。-T 被认为是制表大小。我正在使用 ls 搜索解决方案。有人可以帮我吗？
回答by perreal
Try --time-style=full-iso, or just --full-time:
尝试--time-style=full-iso，或者只是--full-time：
ls -l --time-style=full-iso
ls --full-time
From man-page:
从手册页：
--time-style=STYLE with -l, show times using style STYLE: full-iso, long-iso, iso, locale, +FORMAT. FORMAT is interpreted like
date'; if FORMAT is FORMAT1<newline>FORMAT2, FORMAT1 applies to non-recent files and FORMAT2 to recent files; if STYLE is prefixed withposix-', STYLE takes effect only outside the POSIX locale
--time-style=STYLE 和 -l，使用样式 STYLE 显示时间：full-iso、long-iso、iso、locale、+FORMAT。FORMAT 解释为
date'; if FORMAT is FORMAT1<newline>FORMAT2, FORMAT1 applies to non-recent files and FORMAT2 to recent files; if STYLE is prefixed withposix-'，STYLE 仅在 POSIX 语言环境之外生效
So you can also have a format specifier (see dateman-page for format string):
所以你也可以有一个格式说明符（参见date格式字符串的手册页）：
ls -l --time-style=+"%Y %H:%M:%S"
