Android中的RSA加密解密

RSA Encryption Decryption in Android

提问by Riddhi Barbhaya

I am implementing a demo for RSA Encryption and Decryption in Android. I can Perform Encryption very well, but In Decryption I get an Exception: >>java.security.InvalidKeyException: unknown key type passed to RSA.

我正在 Android 中实现 RSA 加密和解密的演示。我可以很好地执行加密，但在解密中我得到一个异常：>>java.security.InvalidKeyException: unknown key type passed to RSA.

    KeyPairGenerator kpg;
    KeyPair kp;
    PublicKey publicKey;
    PrivateKey privateKey;
    byte [] encryptedBytes,decryptedBytes;
    Cipher cipher,cipher1;
    String encrypted,decrypted;

    public String RSAEncrypt (final String plain) throws NoSuchAlgorithmException, NoSuchPaddingException, InvalidKeyException, IllegalBlockSizeException, BadPaddingException 
    {
        kpg = KeyPairGenerator.getInstance("RSA");
        kpg.initialize(1024);
        kp = kpg.genKeyPair();
        publicKey = kp.getPublic();
        privateKey = kp.getPrivate();

        cipher = Cipher.getInstance("RSA");
        cipher.init(Cipher.ENCRYPT_MODE, publicKey);
        encryptedBytes = cipher.doFinal(plain.getBytes());
        encrypted = new String(encryptedBytes);
        System.out.println("EEncrypted?????"+encrypted);
        return encrypted;

    }

    public String RSADecrypt (final String result) throws NoSuchAlgorithmException, NoSuchPaddingException, InvalidKeyException, IllegalBlockSizeException, BadPaddingException 
    {

        cipher1=Cipher.getInstance("RSA");
        cipher1.init(Cipher.DECRYPT_MODE, privateKey);
        decryptedBytes = cipher1.doFinal(result.getBytes());
        decrypted = new String(decryptedBytes);
        System.out.println("DDecrypted?????"+decrypted);
        return decrypted;

    }

And I am calling the function from here:

我从这里调用函数：

encrypt.setOnClickListener(new OnClickListener()
        { 
            public void onClick(View arg0) 
            {
                    try
                    {
                        RSAEncrypt rsaencrypt=new RSAEncrypt();
                        rsaencrypt.RSAEncrypt(name);

                        result=rsaencrypt.RSAEncrypt(name);
                        Toast.makeText(getBaseContext(), result.toString(),Toast.LENGTH_SHORT).show();

                        System.out.println("Result:"+result);
                    }
                    catch(Exception e)
                    {
                        e.printStackTrace();
                        Toast.makeText(getBaseContext(), e.toString(),Toast.LENGTH_LONG).show();
                    }
            }
        });

        decrypt.setOnClickListener(new OnClickListener()
        { 
            public void onClick(View arg0) 
            {
                {
                    try
                    {
                        RSAEncrypt rsadecrypt=new RSAEncrypt();

                        rsadecrypt.RSADecrypt(result);

                        ans=rsadecrypt.RSADecrypt(result);
                        System.out.println("Result is"+ans);
                        Toast.makeText(getBaseContext(), ans.toString(),Toast.LENGTH_LONG).show();
                    }
                    catch(Exception e)
                    {
                        e.printStackTrace();
                        Toast.makeText(getBaseContext(), e.toString(),Toast.LENGTH_LONG).show();
                        System.out.println("Exception is>>"+e);
                    }
            }
        });

采纳答案by Robert

In RSA you should use the public key for encryption and the private key for decryption.

在 RSA 中，您应该使用公钥进行加密，使用私钥进行解密。

Your sample code uses for encryption and decryption the public key - this can not work.

您的示例代码用于加密和解密公钥 - 这行不通。

Hence in the decryption part you should initialize the cipher this way:

因此，在解密部分，您应该以这种方式初始化密码：

cipher1.init(Cipher.DECRYPT_MODE, privateKey);

Furthermor your code has a second significant bug:

此外，您的代码还有第二个重大错误：

You are converting a byte array with binary content to a String.

您正在将具有二进制内容的字节数组转换为字符串。

Never ever convert binary data to a String!

永远不要将二进制数据转换为字符串！

Strings are for string characters, not binary data. If you want to pack binary data into a String encode it to printable characters for example using Hex or Base64.

字符串用于字符串字符，而不是二进制数据。如果要将二进制数据打包为字符串，请将其编码为可打印的字符，例如使用 Hex 或 Base64。

The following example uses the hexadecimal encoder fro org.apache.common.codecpackage - a third party library with has to be installed.

以下示例使用来自org.apache.common.codec包的十六进制编码器- 必须安装第三方库。

public byte[] RSAEncrypt(final String plain) throws NoSuchAlgorithmException, NoSuchPaddingException,
        InvalidKeyException, IllegalBlockSizeException, BadPaddingException {
    kpg = KeyPairGenerator.getInstance("RSA");
    kpg.initialize(2048);
    kp = kpg.genKeyPair();
    publicKey = kp.getPublic();
    privateKey = kp.getPrivate();

    cipher = Cipher.getInstance("RSA");
    cipher.init(Cipher.ENCRYPT_MODE, publicKey);
    encryptedBytes = cipher.doFinal(plain.getBytes());
    System.out.println("EEncrypted?????" + new String(org.apache.commons.codec.binary.Hex.encodeHex(encryptedBytes)));
    return encryptedBytes;
}

public String RSADecrypt(final byte[] encryptedBytes) throws NoSuchAlgorithmException, NoSuchPaddingException,
        InvalidKeyException, IllegalBlockSizeException, BadPaddingException {

    cipher1 = Cipher.getInstance("RSA");
    cipher1.init(Cipher.DECRYPT_MODE, privateKey);
    decryptedBytes = cipher1.doFinal(encryptedBytes);
    decrypted = new String(decryptedBytes);
    System.out.println("DDecrypted?????" + decrypted);
    return decrypted;
}

回答by Elton da Costa

My class:

我的课：

package com.infovale.cripto;

import java.io.UnsupportedEncodingException;
import java.math.BigInteger;
import java.security.InvalidKeyException;
import java.security.KeyPair;
import java.security.KeyPairGenerator;
import java.security.NoSuchAlgorithmException;
import java.security.PrivateKey;
import java.security.PublicKey;
import java.util.Arrays;

import javax.crypto.BadPaddingException;
import javax.crypto.Cipher;
import javax.crypto.IllegalBlockSizeException;
import javax.crypto.NoSuchPaddingException;

public class RSA {

KeyPairGenerator kpg;
KeyPair kp;
PublicKey publicKey;
PrivateKey privateKey;
byte[] encryptedBytes, decryptedBytes;
Cipher cipher, cipher1;
String encrypted, decrypted;

public String Encrypt (String plain) throws NoSuchAlgorithmException, NoSuchPaddingException, InvalidKeyException, IllegalBlockSizeException, BadPaddingException 
{
    kpg = KeyPairGenerator.getInstance("RSA");
    kpg.initialize(1024);
    kp = kpg.genKeyPair();
    publicKey = kp.getPublic();
    privateKey = kp.getPrivate();

    cipher = Cipher.getInstance("RSA");
    cipher.init(Cipher.ENCRYPT_MODE, publicKey);
    encryptedBytes = cipher.doFinal(plain.getBytes());

    encrypted = bytesToString(encryptedBytes);
    return encrypted;

}

public String Decrypt (String result) throws NoSuchAlgorithmException, NoSuchPaddingException, InvalidKeyException, IllegalBlockSizeException, BadPaddingException 
{           

    cipher1=Cipher.getInstance("RSA");
    cipher1.init(Cipher.DECRYPT_MODE, privateKey);
    decryptedBytes = cipher1.doFinal(stringToBytes(result));
    decrypted = new String(decryptedBytes);
    return decrypted;

}

public  String bytesToString(byte[] b) {
    byte[] b2 = new byte[b.length + 1];
    b2[0] = 1;
    System.arraycopy(b, 0, b2, 1, b.length);
    return new BigInteger(b2).toString(36);
}

public  byte[] stringToBytes(String s) {
    byte[] b2 = new BigInteger(s, 36).toByteArray();
    return Arrays.copyOfRange(b2, 1, b2.length);
}
}

回答by seb

Here is an example for Android of:

以下是 Android 的示例：

• generating a private/public RSA key pair
• encrypting a string
• decrypting the encrypted string

• 生成私有/公共 RSA 密钥对
• 加密一个字符串
• 解密加密字符串

These methods deal with all the base 64 encoding/decoding.

这些方法处理所有 base 64 编码/解码。

    public void TestEncryptData(String dataToEncrypt) {
        // generate a new public/private key pair to test with (note. you should only do this once and keep them!)
        KeyPair kp = getKeyPair();

        PublicKey publicKey = kp.getPublic();
        byte[] publicKeyBytes = publicKey.getEncoded();
        String publicKeyBytesBase64 = new String(Base64.encode(publicKeyBytes, Base64.DEFAULT));

        PrivateKey privateKey = kp.getPrivate();
        byte[] privateKeyBytes = privateKey.getEncoded();
        String privateKeyBytesBase64 = new String(Base64.encode(privateKeyBytes, Base64.DEFAULT));

        // test encryption
        String encrypted = encryptRSAToString(dataToEncrypt, publicKeyBytesBase64);

        // test decryption
        String decrypted = decryptRSAToString(encrypted, privateKeyBytesBase64);
    }

    public static KeyPair getKeyPair() {
        KeyPair kp = null;
        try {
            KeyPairGenerator kpg = KeyPairGenerator.getInstance("RSA");
            kpg.initialize(2048);
            kp = kpg.generateKeyPair();
        } catch (Exception e) {
            e.printStackTrace();
        }

        return kp;
    }

    public static String encryptRSAToString(String clearText, String publicKey) {
        String encryptedBase64 = "";
        try {
            KeyFactory keyFac = KeyFactory.getInstance("RSA");
            KeySpec keySpec = new X509EncodedKeySpec(Base64.decode(publicKey.trim().getBytes(), Base64.DEFAULT));
            Key key = keyFac.generatePublic(keySpec);

            // get an RSA cipher object and print the provider
            final Cipher cipher = Cipher.getInstance("RSA/ECB/OAEPWITHSHA-256ANDMGF1PADDING");
            // encrypt the plain text using the public key
            cipher.init(Cipher.ENCRYPT_MODE, key);

            byte[] encryptedBytes = cipher.doFinal(clearText.getBytes("UTF-8"));
            encryptedBase64 = new String(Base64.encode(encryptedBytes, Base64.DEFAULT));
        } catch (Exception e) {
            e.printStackTrace();
        }

        return encryptedBase64.replaceAll("(\r|\n)", "");
    }

    public static String decryptRSAToString(String encryptedBase64, String privateKey) {

        String decryptedString = "";
        try {
            KeyFactory keyFac = KeyFactory.getInstance("RSA");
            KeySpec keySpec = new PKCS8EncodedKeySpec(Base64.decode(privateKey.trim().getBytes(), Base64.DEFAULT));
            Key key = keyFac.generatePrivate(keySpec);

            // get an RSA cipher object and print the provider
            final Cipher cipher = Cipher.getInstance("RSA/ECB/OAEPWITHSHA-256ANDMGF1PADDING");
            // encrypt the plain text using the public key
            cipher.init(Cipher.DECRYPT_MODE, key);

            byte[] encryptedBytes = Base64.decode(encryptedBase64, Base64.DEFAULT);
            byte[] decryptedBytes = cipher.doFinal(encryptedBytes);
            decryptedString = new String(decryptedBytes);
        } catch (Exception e) {
            e.printStackTrace();
        }

        return decryptedString;
    }

回答by jaredzhang

I think the problem is that you should use the same key pair to encrypt and decrypt the cipher. Referring to the JavaDoc:

我认为问题在于您应该使用相同的密钥对来加密和解密密码。参考 JavaDoc：

 genKeyPair() This will generate a new key pair every time it is called.

回答by Yi?it

when using RSAEcvypt method, its fill PublicKey and private key. And when your Decrypt your generated byte[], your publicKey and privateKey being NULL. Because of that you get this error.

使用RSAEcvypt 方法时，其填写PublicKey 和私钥。当您解密生成的字节 [] 时，您的公钥和私钥为 NULL。因此，您会收到此错误。

You should use your keys static;

您应该使用静态密钥；

enter code here

KeyPairGenerator kpg;
KeyPair kp;
static PublicKey publicKey;
static PrivateKey privateKey;
byte [] encryptedBytes,decryptedBytes;
Cipher cipher,cipher1;
String encrypted,decrypted;