Java 如何使用 JAX-RS 设置和检查 cookie？

How to set and check cookies wih JAX-RS?

提问by Gil404

I am a noobie with RESTful API and I am trying to build a Login service in which I provide an email and password and if the validation is successful - to store a cookie. In addition, how do I check the cookie(if stored)?

我是 RESTful API 的菜鸟，我正在尝试构建一个登录服务，我在其中提供电子邮件和密码，如果验证成功 - 存储 cookie。另外，如何检查cookie（如果已存储）？

How can this be achieved?

如何做到这一点？

@Path("/login")
@POST
@Produces(MediaType.APPLICATION_JSON)
@Consumes({MediaType.APPLICATION_FORM_URLENCODED, MediaType.APPLICATION_JSON})
public Response Login(final String i_LoginDetails) throws JSONException {
    final JSONObject obj = new JSONObject(i_LoginDetails);
    try {
        if (isValidUser(obj.getString("email"), obj.getString("password"))) {
            // Set a cookie
        } else {
            // return error invalid-credentials message
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
    return Response.ok("TEST").build();
}

And how do I check the cookie(if set)?

我如何检查 cookie（如果设置）？

回答by Paul Vargas

You can do the following:

您可以执行以下操作：

• To store a new cookie:

  @GET
  @Path("/login")
  @Produces(MediaType.TEXT_PLAIN)
  public Response login() {
      NewCookie cookie = new NewCookie("name", "123");
      return Response.ok("OK").cookie(cookie).build();
  }
  

• To retrieve the cookie (javax.ws.rs.core.Cookie):

  @GET
  @Path("/foo")
  @Produces(MediaType.TEXT_PLAIN)
  public Response foo(@CookieParam("name") Cookie cookie) {
      if (cookie == null) {
          return Response.serverError().entity("ERROR").build();
      } else {
          return Response.ok(cookie.getValue()).build();
      }
  }
  

  However, you may only want the value:

  @GET
  @Path("/foo")
  @Produces(MediaType.TEXT_PLAIN)
  public Response foo(@CookieParam("name") String value) {
      System.out.println(value);
      if (value == null) {
          return Response.serverError().entity("ERROR").build();
      } else {
          return Response.ok(value).build();
      }
  }
  

• 要存储新的 cookie：

  @GET
  @Path("/login")
  @Produces(MediaType.TEXT_PLAIN)
  public Response login() {
      NewCookie cookie = new NewCookie("name", "123");
      return Response.ok("OK").cookie(cookie).build();
  }
  

• 要检索 cookie ( javax.ws.rs.core.Cookie)：

  @GET
  @Path("/foo")
  @Produces(MediaType.TEXT_PLAIN)
  public Response foo(@CookieParam("name") Cookie cookie) {
      if (cookie == null) {
          return Response.serverError().entity("ERROR").build();
      } else {
          return Response.ok(cookie.getValue()).build();
      }
  }
  

  但是，您可能只需要以下值：

  @GET
  @Path("/foo")
  @Produces(MediaType.TEXT_PLAIN)
  public Response foo(@CookieParam("name") String value) {
      System.out.println(value);
      if (value == null) {
          return Response.serverError().entity("ERROR").build();
      } else {
          return Response.ok(value).build();
      }
  }
  

---

---

By the way, you may want to try the following code:

顺便说一句，您可能想尝试以下代码：

@GET
@Path("/logout")
@Produces(MediaType.TEXT_PLAIN)
public Response logout(@CookieParam("name") Cookie cookie) {
    if (cookie != null) {
        NewCookie newCookie = new NewCookie(cookie, null, 0, false);
        return Response.ok("OK").cookie(newCookie).build();
    }
    return Response.ok("OK - No session").build();
}

This removes the cookie in the browser. The behavior depends on the implementation of JAX-RS. With RESTEasy (JBoss AS 7.0) and Google Chrome works fine.

这将删除浏览器中的 cookie。该行为取决于 JAX-RS 的实现。使用 RESTEasy (JBoss AS 7.0) 和 Google Chrome 可以正常工作。