php 非静态方法 ..... 不应静态调用
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Non-static method ..... should not be called statically
提问by Novice Hobby PHP Boy
I have recently done an update to PHP 5.4, and I get an error about static and non-static code.
我最近对 PHP 5.4 进行了更新，但出现关于静态和非静态代码的错误。
This is the error:
这是错误：
PHP Strict Standards: Non-static method VTimer::get()
should not be called statically in /home/jaco/public_html/include/function_smarty.php on line 371
This is the line 371:
这是第 371 行：
$timer = VTimer::get($options['magic']);
I hope somebody can help.
我希望有人可以提供帮助。
回答by mamdouh alramadan
That means it should be called like:
这意味着它应该被称为：
$timer = (new VTimer)->get($options['magic']);
$timer = (new VTimer)->get($options['magic']);
The difference between staticand non-staticis that the first one doesn't need initialization so you can call the classnamethen append ::to it and call the method immediately.
Like so:
static和之间的区别在于non-static第一个不需要初始化，因此您可以调用classnamethen 附加::到它并立即调用该方法。像这样：
ClassName::method();
and if the method is not static you need to initialize it like so:
如果该方法不是静态的，则需要像这样初始化它：
$var = new ClassName();
$var->method();
However, in PHP 5.4 you can use this syntax instead as a shorthand:
但是，在 PHP 5.4 中，您可以使用以下语法作为速记：
(new ClassName)->method();
回答by deadghost
You can also change the method to be static like so:
您还可以将方法更改为静态，如下所示：
class Handler {
public static function helloWorld() {
echo "Hello world!";
}
}
回答by Particle Effect
The most elegant way would be :
最优雅的方式是：
(new ClassName)->method();
You can also convert your function to static function call() {}, but that depends on your function and what you're doing with it.
您也可以将您的函数转换为static function call() {}，但这取决于您的函数以及您使用它做什么。
If you need to instantiate a class then avoid doing so, treat static functions like constants, they can not have objects and require predefined variables.
如果您需要实例化一个类，请避免这样做，将静态函数视为常量，它们不能有对象并需要预定义的变量。
