Java 如何检查某个位置的字符串是否包含字符啊？
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How to check if a string at a certain position contains character a-h?
提问by ToonLink
I know there must be a simpler way to check, but this is what I'm doing right now.
我知道必须有一种更简单的检查方法，但这就是我现在正在做的。
if (g.charAt(0) == 'a' || g.charAt(0) =='b' || g.charAt(0) =='c' ||
g.charAt(0) == 'd' || g.charAt(0) =='e' || g.charAt(0) =='f' ||
g.charAt(0) == 'g' || g.charAt(0) =='h')
采纳答案by user2864740
Relying on character ordering and that a..h is a consecutive range:
依靠字符排序并且a..h 是一个连续的范围：
char firstChar = g.charAt(0);
if (firstChar >= 'a' && firstChar <= 'h') {
// ..
}
回答by Makoto
Use a regular expression for this one. Cut the first character of your String as a substring, and match on it.
为此使用正则表达式。将 String 的第一个字符剪切为子字符串，并对其进行匹配。
if(g.substring(0, 1).matches("[a-h]") {
// logic
}
回答by hemanth
Another way of doing it :
另一种方法：
if(Array.asList("abcdefgh".toCharArray()).contains(g.charAt(0)))
{
//Logic
}
回答by Mario Carneiro
A variation on hemanth's answer:
hemanth 答案的变体：
if("abcdefgh".contains(g.substring(0,1))) do_something();
or
或者
if("abcdefgh".indexOf(g.charAt(0)) >= 0) do_something();
