Ruby-on-rails 格式化日期对象以显示人类可读的日期
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Formatting a date object to display a human readable date
提问by sergserg
Here's what I'd like to display:
这是我想显示的内容：
May 13, 2012
Here's what is being displayed:
这是显示的内容：
2012-05-13
I searched for some answers and it led me to "Formatting Dates and Floats in Ruby", where it mentions a possible solution:
我搜索了一些答案，它让我找到了“在 Ruby 中格式化日期和浮点数”，其中提到了一个可能的解决方案：
<p class="date"><%= @news_item.postdate.to_s("%B %d, %Y") %></p>
However this doesn't change the output at all. No debugging errors, or exceptions are fired.
然而，这根本不会改变输出。没有调试错误或异常被触发。
I can do this and it works perfectly fine:
我可以做到这一点，它工作得很好：
<p class="date"><%= Time.now.to_s("%B %d, %Y") %></p>
Here is my migration file (to see what data type I used):
这是我的迁移文件（查看我使用的数据类型）：
class CreateNewsItems < ActiveRecord::Migration
def change
create_table :news_items do |t|
t.date :postdate
t.timestamps
end
end
end
回答by Casper
Date.to_sis not the same as Time.to_s. Your postdateis a Date, so therefore you might want to look at strftimeinstead:
Date.to_s不一样Time.to_s。您postdate是 a Date，因此您可能需要查看strftime：
postdate.strftime("%B %d, %Y")
Or even look to add your own custom date format to your Rails app:
Need small help in converting date format in ruby
或者甚至希望将您自己的自定义日期格式添加到您的 Rails 应用程序：
在 ruby 中转换日期格式需要一些帮助
回答by FernandoEscher
The to_formatted_sfunction already has some common human readable formats for DateTimeobjects in Rails.
该to_formatted_s功能已经有一些共同的人类可读的格式DateTime在Rails的对象。
datetime.to_formatted_s(:db) # => "2007-12-04 00:00:00"
datetime.to_formatted_s(:short) # => "04 Dec 00:00"
datetime.to_formatted_s(:long) # => "December 04, 2007 00:00"
datetime.to_formatted_s(:long_ordinal) # => "December 4th, 2007 00:00"
datetime.to_formatted_s(:rfc822) # => "Tue, 04 Dec 2007 00:00:00 +0000"
datetime.to_formatted_s(:iso8601) # => "2007-12-04T00:00:00+00:00"
