Java - 从字符串中修剪前导或尾随字符?
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Java - Trim leading or trailing characters from a string?
提问by Brad Parks
How can I trim the leading or trailing characters from a string in java?
java - 如何从java中的字符串中修剪前导或尾随字符?
For example, the slash character "/" - I'm not interested in spaces, and am looking to trim either leading or trailing characters at different times.
例如,斜杠字符“/” - 我对空格不感兴趣,并且希望在不同时间修剪前导或尾随字符。
采纳答案by Reimeus
You could use
你可以用
Leading:
领导:
System.out.println("//test/me".replaceAll("^/+", ""));
Trailing:
尾随:
System.out.println("//test/me//".replaceAll("/+$", ""));
回答by Brad Parks
You can use Apache StringUtils.stripStartto trim leading characters, or StringUtils.stripEndto trim trailing characters.
您可以使用 Apache StringUtils.stripStart修剪前导字符,或使用StringUtils.stripEnd修剪尾随字符。
For example:
例如:
System.out.println(StringUtils.stripStart("//test/me", "/"));
will output:
将输出:
test/me
考验我
Note that if for some reason you can't use the whole StringUtils library, you could just rip out the relevant parts, as detailed here:
请注意,如果由于某种原因您不能使用整个 StringUtils 库,您可以删除相关部分,详情如下:
回答by Andrushenko Alexander
My version of trimming leading and/or trailing String s from String str. Both arguments may be null. When str does not has leading and/or trailing s, it is not changed.
我从 String str 修剪前导和/或尾随 String 的版本。两个参数都可以为空。当 str 没有前导和/或尾随 s 时,它不会改变。
String trim(String str, String s) {
String res = s == null ? str : str == null ? null : s.length() >= str.length() ? str : str.replaceFirst(s, "");
if ((res != null) && (s != null) && (res.length() >= s.length())) {
return res.substring(res.length() - s.length(), res.length()).equals(s) ? res.substring(0, res.length() - s.length()) : res;
}
return res;
}
回答by Oleg
You could use a simple iteration if you want to remove the leading characters from a string :
如果要从字符串中删除前导字符,可以使用简单的迭代:
String removeLeadingChar(String s, char c) {
int i;
for(i = 0; i < s.length() && s.charAt(i) == c; ++i);
return s.substring(i);
}
same logic applies if you want to remove any trailing char
.
如果您想删除任何尾随char
.
回答by Minhas Kamal
Trim with Character, String, or Regex
用字符、字符串或正则表达式修剪
If run-time is not a big issue for you, then this code will prove really helpful.
如果运行时对您来说不是大问题,那么此代码将证明非常有用。
public class StringTrimmer {
public static String trim(String string, char ch){
return trim(string, ch, ch);
}
public static String trim(String string, char leadingChar, char trailingChar){
return string.replaceAll("^["+leadingChar+"]+|["+trailingChar+"]+$", "");
}
public static String trim(String string, String regex){
return trim(string, regex, regex);
}
public static String trim(String string, String leadingRegex, String trailingRegex){
return string.replaceAll("^("+leadingRegex+")+|("+trailingRegex+")+$", "");
}
// test
public static void main(String[] args) {
System.out.println(trim("110100", '1', '0')); // outputs: 01
System.out.println(trim("**Aa0*#**", '*')); // outputs: Aa0*#
System.out.println(trim("123##22222", "12", "22")); // outputs: 3##2
System.out.println(trim("101101##10101", "101")); // outputs: ##10
System.out.println(trim("123##abcde", "\d", "[c-e]")); // outputs: ##ab
}
}
回答by Gabriel Gates
For those using Spring:
对于使用 Spring 的用户:
import org.springframework.util.StringUtils;
public void setFileName(String fileName) {
// If the extension does not exist trim the trailing period
this.fileName = StringUtils.trimTrailingCharacter(fileName,'.');
}