Python 请求 - 通过 GET 传递参数
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Python Requests - pass parameter via GET
提问by Cody Raspien
I am trying to call an API and pass some parameters to it.
我正在尝试调用 API 并向其传递一些参数。
My endpoint should look like:
我的端点应如下所示：
https://example.com?q=foodfood is the parameter
https://example.com?q=foodfood 是参数
import requests
parametervalue = "food"
r = requests.get("https://example.com/q=", parametervalue)
When I do print r.url, I do not get the correct result - the value is not passed.
当我打印 r.url 时，我没有得到正确的结果 - 没有传递值。
Updated:
更新：
Error:
错误：
r = requests.get('https://example.com', params={'1':parametervalue})
File "/usr/lib/python2.7/dist-packages/requests/api.py", line 55, in get
return request('get', url, **kwargs)
Update:
更新：
Answer posted below. Thank you.
答案贴在下面。谢谢你。
Note: The SSL error mentioned in the post was due to me running Python 2.7. I used python3 and it fixed the issue.
注意：帖子中提到的 SSL 错误是由于我运行的是 Python 2.7。我使用了 python3，它解决了这个问题。
回答by Pitto
Here's the relevant code to perform a GET http call from the official documentation
这是从官方文档中执行 GET http 调用的相关代码
import requests
payload = {'key1': 'value1', 'key2': 'value2'}
r = requests.get('http://httpbin.org/get', params=payload)
In order to adapt it to your specific request:
为了使其适应您的特定要求：
import requests
payload = {'q': 'food'}
r = requests.get('http://httpbin.org/get', params=payload)
print (r.text)
Here's the obtained result if I run the 2nd example:
如果我运行第二个示例，这是获得的结果：
python request_test.py
{"args":{"q":"food"},"headers":{"Accept":"*/*","Accept-Encoding":"gzip, deflate","Connection":"close","Host":"httpbin.org","User-Agent":"python-requests/2.18.1"},"origin":"x.y.z.a","url":"http://httpbin.org/get?q=food"}
