[-f: 命令未找到，Bash 脚本文件存在
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[-f: Command not found, Bash script does file exist
提问by Wilken
I'm having an issue with a script that I am trying to program. Narrowed down and simplified code and it gives an error that command is not found. If i do "test -f file" in command line it returns nothing, not command not found
我正在尝试编写的脚本有问题。缩小和简化代码，它给出了找不到命令的错误。如果我在命令行中执行“test -f file”，它不会返回任何内容，而不是找不到命令
PATH=
#!/bin/bash
DIR=
if [[-f $PATH]]; then
echo expression evaluated as true
else
echo expression evaluated as false
fi
exit
Here is the actual more complicated script I'm trying to run
这是我尝试运行的实际更复杂的脚本
verify()
{
if [[-f ]]; then
VFY[]="f"
echo " is a file"
elif [[-d ]]
then
VFY[]="d"
echo " is a directory"
else
VFY[]=0
echo -e "\r"
echo " is neither a file or a directory"
echo -e "\r"
fi
}
Its part of a larger script that can move things around depending on inputs. I've run this in CentOS 6, and FreeBSD, both give the same error "[[-f: Command not found"
它是更大脚本的一部分，可以根据输入移动内容。我已经在 CentOS 6 和 FreeBSD 中运行了它，两者都给出了相同的错误“[[-f: Command not found”
回答by Edouard Thiel
Simply add an extra space between [[and -f, and also before ]].
只需在[[和之间以及-f之前添加一个额外的空格]]。
You will get:
你会得到：
#! /bin/bash
DIR=${1-} # unused in your example
if [[ -f test.sh ]]; then
echo "expression evaluated as true"
else
echo "expression evaluated as false"
fi
exit
and for your function
和你的功能
verify() # file ind
{
local file= ind=
if [[ -f "$file" ]]; then
VFY[ind]="f" # no need of $ for ind
echo "$file is a file"
elif [[ -d "$file" ]]; then
VFY[ind]="d"
echo "$file is a directory"
else
VFY[ind]=0
echo -e "\n$file is neither a file or a directory\n"
fi
}
